Question 5

# For which value of k does the following pair of equations yield a unique solution for x such that the solution is positive?$$x^2 - y^2 = 0$$$$(x-k)^2 + y^2 = 1$$

Solution

From 1st equation we know that $$(x)^2 = y^2$$

Substituting this in 2nd equation. we get , $$2*x^2 - 2*x*k + k^2-1 =0$$ and for unique solution $$b^2-4ac=0$$ must satisfy.

This is possible only when k = $$\sqrt{2}$$