Question 47

If $$xy + yz + zx = 0$$, then $$(x + y + z)^2$$ equals

Solution

$$(x+y+z)^2 = x^2 + y^2 + z^2 + 2(xy + yz + xz)$$
as $$xy+yz+xz = 0$$
so equation will be resolved to $$x^2 + y^2 + z^2$$

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