Question 4

The equation of a line is given by 4y-6x+9=0. Find the slope of other line which is perpendicular to it.

Solution

Slope of line having equation $$ax+by+c=0$$ is $$\frac{-a}{b}$$

Slope of line $$-6x+4y+9=0$$ is $$\frac{-(-6)}{4}=\frac{3}{2}$$

Product of slopes of two perpendicular lines = -1

=> Slope of other line which is perpendicular to it = $$\frac{-2}{3}$$

=> Ans - (A)

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