The equation of a line is given by 4y-6x+9=0. Find the slope of other line which is perpendicular to it.
Slope of line having equation $$ax+by+c=0$$ is $$\frac{-a}{b}$$
Slope of line $$-6x+4y+9=0$$ is $$\frac{-(-6)}{4}=\frac{3}{2}$$
Product of slopes of two perpendicular lines = -1
=> Slope of other line which is perpendicular to it = $$\frac{-2}{3}$$
=> Ans - (A)
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