Solution
$$\frac{9x^{2}-24xy+16y^{2}}{3x-4y}$$
=$$\frac{(3x-4y)^{2}}{3x-4y}=3x-4y$$
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$$\frac{9x^{2}-24xy+16y^{2}}{3x-4y}$$
=$$\frac{(3x-4y)^{2}}{3x-4y}=3x-4y$$
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