RRB 2008 Kolkata

Question 28

If $$(25)^{x - 3} = (125)^{2x - 3}$$, then x is equal to

Solution

$$(25)^{x - 3} = (125)^{2x - 3}$$

=$$(5)^{2(x-3)}=(5)^{3(2x-3)}$$

equating the powers we get,

$$2x-6=6x-9$$

=>$$x=\frac{3}{4}$$

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