If $$(25)^{x - 3} = (125)^{2x - 3}$$, then x is equal to
$$(25)^{x - 3} = (125)^{2x - 3}$$
=$$(5)^{2(x-3)}=(5)^{3(2x-3)}$$
equating the powers we get,
$$2x-6=6x-9$$
=>$$x=\frac{3}{4}$$
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