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Question 27
Evaluate :- $$\frac{16 \times2^{n+1 }-4\times2^{n}}{16\times 2^{n+2}-2\times2^{n+2}}$$
Solution
$$\frac{16 \times2^{n+1 }-4\times2^{n}}{16\times 2^{n+2}-2\times2^{n+2}}$$
=$$\frac{2^{n}(32-4)}{2^{n+2}(16-2)}$$
=$$\frac{28}{4(14)}$$=$$\frac{1}{2}$$
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