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Question 26
The number of common terms in the two sequences: 15, 19, 23, 27, . . . . , 415 and 14, 19, 24, 29, . . . , 464 is
Solution
A: 15, 19, 23, 27, . . . . , 415
B: 14, 19, 24, 29, . . . , 464
Here the first common term = 19
Common difference = LCM of 5, 4=20
19+(n-1)20 $$\le\ $$ 415
(n-1)20 $$\le\ $$ 396
(n-1) $$\le\ $$ 19.8
n=20
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