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What is the value of $$(sin 60^\circ - 2\sqrt{3})$$?
Expression : $$(sin 60^\circ - 2\sqrt{3})$$
= $$\frac{\sqrt3}{2}-2\sqrt3$$
= $$\frac{\sqrt3-4\sqrt3}{2}=\frac{-3\sqrt3}{2}$$
=> Ans - (D)
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