An alloy is prepared by mixing three metals A, B and C in the proportion 3 : 4 : 7 by volume. Weights of the same volume of the metals A. B and C are in the ratio 5 : 2 : 6. In 130 kg of the alloy, the weight, in kg. of the metal C is
Let the volume of Metals A,B,C we 3x, 4x, 7x
Ratio weights of given volume be 5y,2y,6y
.'. 15xy+8xy+42xy=130 => 65xy=130 => xy=2.
.'.`The weight, in kg. of the metal C is 42xy=84.
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1 year, 8 months ago
15*XY+8xy+42xy = 65xy = 130... kindly correct the solution