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The graph of linear equation y = x passes through the point
$$\left(\begin{array}{c}0,\frac{3}{2}\end{array}\right)$$
(1,1)
$$\left(\begin{array}{c}-\frac{1}{2},\frac{1}{2}\end{array}\right)$$
$$\left(\begin{array}{c}\frac{3}{2},-\frac{3}{2}\end{array}\right)$$
Only option B satisfies the given equation i.e
After substituting x=1 and y=1 in the given equation we get LHS equal to RHS.
Hence, option B is the correct answer.
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