If $$x +\frac{1}{x}=3,$$ then the value of $$x^{2} + \frac{1}{x^{2}}$$ is
Given, $$x +\frac{1}{x} = 3$$
Squaring on both sides, we get
$$x^{2} + \frac{1}{x^{2}} + 2 = 9$$
$$x^{2} + \frac{1}{x^{2}} = 7$$
Hence, option D is the correct answer.
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