If I walk at 5 km/hour, I miss a train by 7 minutes. If, however, I walk at 6 km/hour, I reach the station 5 minutes before the departure of the train. The distance (in km between my house and the station is
When speed is 5 km/hour time is t + (7/60) hours
When speed is 6 km/hour time is t - (5/60) hours
Distance is same.Hence the product of speed and time must be same.
5 (t + (7/60)) = 6(t - (5/60)
5t + (7/12) = 6t - (1/2)
t=(7/12)+(1/2)
t = 13/12 hours
Distance = 5 ( t + (7/60) )
=5t + (7/12)
=5 (13/12) + (7/12) = 72/12
=6 kms.
Hence Option A is the correct answer.
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