Walking 6/7 th of his usual speed, a man is 12 minutes too late. The usual time taken by him to cover that distance is
Speed = $$s$$
Time =$$ t mins$$
Time taken when the man walks at $$\frac{6}{7}$$ th of his speed $$= t+12$$
Since distance is same the product of speed and time must be same.
$$\frac{6\times (t+12)}{7} = t$$
t= 72 mins = 1 hour and 12 minutes
Hence Option B is the correct answer.
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