Question 139

In an isosceles triangle DEF, ∠D = 130°. If I is the incentre of the triangle, then what is the value (in degrees) of ∠EIF?

Solution

Given : I is the incentre of $$\triangle$$ DEF and $$\angle$$ D = 130°

To find : $$\angle$$ EIF = $$\theta$$ = ?

Incentre of a triangle = $$90^\circ+\frac{\angle D}{2}$$

=> $$\theta=90^\circ+\frac{130^\circ}{2}$$

=> $$\theta=90^\circ+65^\circ$$

=> $$\theta=155^\circ$$

=> Ans - (C)

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