Question 140
In the following figure, O is the centre of the circle and $$\ \angle$$PRQ = $$\ 50^\circ$$. What is the value (in degrees) of $$\ \angle$$PTQ?
Solution
Given : $$\ \angle$$PRQ = $$\ 50^\circ$$
To find : $$\ \angle$$PTQ = ?
Solution : Quadrilateral PRQT is a cyclic quadrilateral, in which opposite angles are supplementary.
=> $$\angle$$ PRQ + $$\angle$$ PTQ = $$180^\circ$$
=> $$\angle$$ PTQ = $$180^\circ-50^\circ=130^\circ$$
=> Ans - (C)
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