Question 140

In the following figure, O is the centre of the circle and $$\ \angle$$PRQ = $$\ 50^\circ$$. What is the value (in degrees) of $$\ \angle$$PTQ?

Solution

Given : $$\ \angle$$PRQ = $$\ 50^\circ$$

To find : $$\ \angle$$PTQ = ?

Solution : Quadrilateral PRQT is a cyclic quadrilateral, in which opposite angles are supplementary.

=> $$\angle$$ PRQ + $$\angle$$ PTQ = $$180^\circ$$

=> $$\angle$$ PTQ = $$180^\circ-50^\circ=130^\circ$$

=> Ans - (C)

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