Question 133

In $$\triangle$$ABC, AB = AC and is a point on side AC such that BD = BC, IfAB = 12.5 cm and BC = 5 cm, then what is the measure of DC?

Solution

$$\triangle ABC and \triangle$$ BCD are similar triangle because-

BC is common line.

AB = AC and BD = DC

so,

$$\frac{AB}{BC} = \frac{BC}{DC}$$

$$\frac{12.5}{5} = \frac{5}{DC}$$

DC = $$\frac{25}{12.5}$$ = 2 cm

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