Question 134

The value ok $$\frac{\left(1\frac{1}{9} \times 1 \frac{1}{20} \div \frac{21}{38} - \frac{1}{3}\right) \div \left(2\frac{4}{9} \div 1\frac{7}{15} of \frac{3}{5}\right)}{\frac{1}{5} of \frac{1}{5} \div \frac{1}{125} - \frac{1}{25} \div \frac{1}{5} of \frac{1}{5}}$$ lies between .........

Solution

$$\frac{\left(1\frac{1}{9} \times 1 \frac{1}{20} \div \frac{21}{38} - \frac{1}{3}\right) \div \left(2\frac{4}{9} \div 1\frac{7}{15} of \frac{3}{5}\right)}{\frac{1}{5} of \frac{1}{5} \div \frac{1}{125} - \frac{1}{25} \div \frac{1}{5} of \frac{1}{5}}$$ 

=$$\frac{\left(\frac{10}{9} \times  \frac{21}{20} \div \frac{21}{38} - \frac{1}{3}\right) \div \left(\frac{22}{9} \div \frac{22}{25} \right)}{\frac{1}{25}  \div \frac{1}{125} - \frac{1}{25} \div \frac{1}{25}}$$

=$$\frac{\left(\frac{10}{9} \times \frac{19}{10} - \frac{1}{3}\right) \div \left(\frac{25}{9} \right)}{5 - 1}$$

=$$\frac{\left(\frac{19}{9} - \frac{1}{3}\right) \div \left(\frac{25}{9} \right)}{4}$$

=$$\frac{\left(\frac{16}{9} \right) \times  \left(\frac{9}{25} \right)}{4}$$

= $$\frac{4}{25}$$ = 0.16


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