Sign in
Please select an account to continue using cracku.in
↓ →
Suppose hospital A admitted 21 less Covid infected patients than hospital B, and all eventually recovered. The sum of recovery days for patients in hospitals A and B were 200 and 152, respectively. If the average recovery days for patients admitted in hospital A was 3 more than the average in hospital B then the number admitted in hospital A was
Correct Answer: 35
Let the number of Covid patients in Hospitals A and B be x and x+21, respectively. Then, it has been given that:
$$\dfrac{200}{x}-\dfrac{152}{x+21}=3$$
$$\dfrac{\left(200x+4200-152x\right)}{x\left(x+21\right)}=3$$
$$\dfrac{\left(48x+4200\right)}{x\left(x+21\right)}=3$$
$$16x+1400=x\left(x+21\right)$$
$$x^2+5x-1400=0$$
(x+40)(x-35)=0
Hence, x=35.
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for CAT preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.