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In a geometric progression with positive common ratio, the ratio of $$13^{th}$$ term to the $$7^{th}$$ term is 27 : 1 then the ratio of its $$9^{th}$$ term to $$16^{th}$$ term is
$$\frac{1}{3\sqrt{3}}$$
$$\frac{1}{9}$$
$$\frac{1}{9\sqrt{3}}$$
$$\frac{1}{27\sqrt{3}}$$
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