Question 128

Given that $$1^{2}+2^{2}+3^{2}+.....+10^{2}=385$$ the value of $$2^{2}+4^{2}+6^{2}+....20^{2}=$$

Solution

Given that $$1^{2}+2^{2}+3^{2}+.....+10^{2}=385$$

Now,

$$2^{2}+4^{2}+6^{2}+....20^{2}=(1^{2}+2^{2}+3^{2}+.....+10^{2}) \times 2^2 = 4 \times 385 = 1540$$

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App