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Question 128
Given that $$1^{2}+2^{2}+3^{2}+.....+10^{2}=385$$ the value of $$2^{2}+4^{2}+6^{2}+....20^{2}=$$
Solution
Given that $$1^{2}+2^{2}+3^{2}+.....+10^{2}=385$$
Now,
$$2^{2}+4^{2}+6^{2}+....20^{2}=(1^{2}+2^{2}+3^{2}+.....+10^{2}) \times 2^2 = 4 \times 385 = 1540$$Create a FREE account and get:
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