Question 127

If $$\theta$$=60°then $$\frac{1}{2}\sqrt{1+\sin\theta}+ \frac{1}{2}\sqrt{1-\sin\theta}$$ is equal to

at $$\theta$$=60°

sin 60 = $$\frac{\sqrt3}{2}$$

So,

$$\frac{1}{2}\sqrt{1+\sin 60}+ \frac{1}{2}\sqrt{1-\sin60}$$ =

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