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Question 126
A is 40% less than B, and C is 40% of the sum of A and B. The difference between A and B is what percentage of C?
Solution
Let $$B = 10$$, => $$A = 6$$
=> $$C = \frac{40}{100}\times(10+6)=6.4$$
$$\therefore$$ Required % = $$\frac{(B-A)}{C}\times100$$
= $$\frac{4}{6.4}\times100=62.5\%$$
=> Ans - (C)
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