SSC CGL 2012 Tier 1 1 July NZ Morning III

Question 110

The side BC of ΔABC is produced to D. If ∠ACD = 108° and ∠B = ∠A/2, then ∠A is

Solution

We know that the exterior angle is equal to the sum of opposite interior angles.
∠ACD = ∠ABC + ∠BAC
Given, ∠B = $$\frac{\angle A} {2}$$
108° = $$\frac{\angle A} {2}$$ + ∠A
∠A = (108 × 2)/3 = 72°.

Share on Whatsapp Share on Whatsapp

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App