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Question 109
In the following figure, O is the centre of the circle and XO is perpendicular to OY. If the area of the triangle XOY is 32, then the area of the circle is
Solution
Since, OX and OY are perpendicular and also radii of circle.
From, the area of triangle =12×OX×OY=12×OX×OY
= 32
r2 = 2 × 32 = 64.
r = 8.
∴ The area of circle = πr2 = 64π
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