Question 109

In the following figure, O is the centre of the circle and XO is perpendicular to OY. If the area of the triangle XOY is 32, then the area of the circle is

Solution

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Since, OX and OY are perpendicular and also radii of circle.
From, the area of triangle =12×OX×OY=12×OX×OY = 32
r2 = 2 × 32 = 64.
r = 8.

∴ The area of circle = πr2 = 64π

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