When $$2^{33}$$ is divided by 10, the remainder will be
$$\frac{2^{33}}{10}$$ = > $$\frac{8^{11}}{10}$$ => $$\frac{-2^{11}}{10}$$
= > $$\frac{1024 \times -2}{10}$$
= > $$\frac{12}{10}$$ --> remainder 2
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