[Download PDF] TS Police SI Mains 2018 Arithmetic and Reasoning Paper with Solutions

Instructions

For the following questions answer them individually

Question 81

A person put one coin at 1’O clock, two coins at 2’O clock, 3 coins at 3°O clock and so on in a box.Then the number of coins he has put in the box between 6:30 am to 6:30pm in a day is

Video Solution

Solution

From 7AM to 6PM, all numbers from 1 to 12 would have been come across by.
So the total is = 1+2+3....+11+12 = 78

Instructions

The following diagram shows the expenditure of a company on different heads A, B, C, D, E in the year 2018. Based on the information given in below figure answer the following questions

Question 82

If the amount spent on head A is Rs. 90,000 more than the amount spent oC, then the amount spent on E in rupees is

Video Solution

Solution

Amount spent on is twice than on C.
Hence, amount spent on C = 90,000

Now, for amount spent on E, we use direct variation:
$$\frac{90,000}{60}=\frac{?}{70}$$
? = 1,05,000

Question 83

If the amount spent on B is Rs. 1,96,000, then the amount spent on A and E together, in rupees, is

Video Solution

Solution

A and E together correspond to 190 degrees
Using direct Variation:
$$\frac{196000}{80}=\frac{?}{190}$$
? = 4,65,500

Instructions

For the following questions answer them individually

Question 84

A dealer gets 10% of profit afier giving 10% discount on the marked price of anarticle. If the cost price of the article is Rs. 9000, its marked price, in rupees, is

Video Solution

Solution

0.9*MP = 1.1*CP = 1.1*9000 = 9900
MP = 9900/0.9 = 11,000

Question 85

By selling an article each for Rs.600/- a trader get 10% profit on one end and 10% loss on other . The result in the transaction is

Video Solution

Solution

CP of article on which profit was made = 600/1.1 = 6000/11 rupees
CP of article on which loss was made = 600/0.9 = 6000/9 rupees

Total cost price = 40,000/33 rupees
Total selling price = 1200 = 39600/33 rupees

Hence, it is a loss. The only option with a loss is B.

Question 86

Consider the following statements.
A. If the radius ofa sphereis increased by 8%, then the Percentage increase in its surface area is 20.86.
B. Ifthe side of'a cubeis increased by 12%, then the percentageincreasein its surface area 1s 25.44.
C. Ifthe radius of acircle is increased by 16%, then the percentage increasein its area is 34.56.
The correct statements among these are

Video Solution

Solution

If the surface area of original sphere is A, then after increasing radius by 8%, new surface area = 1.08*1.08*A = 1.1664*A
16.64% increase in area

If the surface area of original cube is A, then after increasing side by 12%, new surface area = 1.12*1.12*A = 1.2544*A
25.44% increase in area.

If the area of original circle is A, then after increasing radius by 16%, new area = 1.16*1.16*A = 1.3456*A
34.56% increase in area.

Question 87

The area of the regular hexagon of side 12 cm in square centimeters, is

Video Solution

Solution

Area of hexagon = $$\frac{3\sqrt{\ 3}}{2}\cdot\left(side\right)^2$$
Putting side = 12 cm, we get area = 216*(root 3)

Question 88

The area of a rectangle is 6 times that of a square. If the length of the rectangle is 16 cm more and the breadth of the rectangle is 8 cm morethan the side of the square, then the perimeter of the rectangle, in cm, is

Video Solution

Solution

Let side of square = S
Hence, (S+16)*(S+8) = 6*S*S
$$S^2+24S+128=6S^2$$
$$5S^2-24S-128=0$$

Solving for S, we get S = 8
Hence, length of rectangle = 24 cm and breadth = 16
Perimeter of rectancgle = 80 cm

Question 89

A rectangular wooden piece of dimensions $$8 cm \times 6 cm \times 5 cm$$ cut in to pieces of dimensions $$\frac{5}{4} cm \times \frac{3}{8} cm \times \frac{1}{4} cm$$.then the number of pieces are

Video Solution

Solution

Number of pieces
= Volume of original piece/Volume of each cut piece
= $$\frac{\left(8\cdot6\cdot5\right)}{\frac{5}{4}\cdot\frac{3}{8}\cdot\frac{1}{4}}$$
= $$8\cdot2\cdot4\cdot8\cdot4$$
= $$2^{11}$$

Question 90

If a right circular cone has height 56 cm and base radius 42 cm, then its curved surface area, in square centimeters, is (Take $$\pi = \frac{22}{7}$$)

Video Solution

Solution

Given, height of the right circular cone h = 56 cm

Radius of the right circular cone r = 42 cm

The slant height of the cone l = $$\sqrt{56^2+42^2}$$ = $$\sqrt{3136+1764}$$ = $$\sqrt{3136+1764}$$ = $$\sqrt{4900}$$ = 70 cm

Curved surface area of the cone = $$\pi rl$$

$$=\frac{22}{7}\left(42\right)\left(56\right)$$

$$=$$ 9240 sq.cm

CAT Content

TS Police SI Mains 2018 Arithmetic and Reasoning

TS Police SI Mains 2018 Arithmetic and Reasoning

A person put one coin at 1’O clock, two coins at 2’O clock, 3 coins at 3°O clock and so on in a box.Then the number of coins he has put in the box between 6:30 am to 6:30pm in a day is

If the amount spent on head A is Rs. 90,000 more than the amount spent oC, then the amount spent on E in rupees is

If the amount spent on B is Rs. 1,96,000, then the amount spent on A and E together, in rupees, is

A dealer gets 10% of profit afier giving 10% discount on the marked price of anarticle. If the cost price of the article is Rs. 9000, its marked price, in rupees, is

By selling an article each for Rs.600/- a trader get 10% profit on one end and 10% loss on other . The result in the transaction is

The area of the regular hexagon of side 12 cm in square centimeters, is

The area of a rectangle is 6 times that of a square. If the length of the rectangle is 16 cm more and the breadth of the rectangle is 8 cm morethan the side of the square, then the perimeter of the rectangle, in cm, is

A rectangular wooden piece of dimensions $$8 cm \times 6 cm \times 5 cm$$ cut in to pieces of dimensions $$\frac{5}{4} cm \times \frac{3}{8} cm \times \frac{1}{4} cm$$.then the number of pieces are

If a right circular cone has height 56 cm and base radius 42 cm, then its curved surface area, in square centimeters, is (Take $$\pi = \frac{22}{7}$$)

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