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If a right circular cone has height 56 cm and base radius 42 cm, then its curved surface area, in square centimeters, is (Take $$\pi = \frac{22}{7}$$)
Given, height of the right circular cone h = 56 cm
Radius of the right circular cone r = 42 cm
The slant height of the cone l = $$\sqrt{56^2+42^2}$$ = $$\sqrt{3136+1764}$$ = $$\sqrt{3136+1764}$$ = $$\sqrt{4900}$$ = 70 cm
Curved surface area of the cone = $$\pi rl$$
$$=\frac{22}{7}\left(42\right)\left(56\right)$$
$$=$$ 9240 sq.cm
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