Question 88

The area of a rectangle is 6 times that of a square. If the length of the rectangle is 16 cm more and the breadth of the rectangle is 8 cm morethan the side of the square, then the perimeter of the rectangle, in cm, is

Solution

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Let side of square = S
Hence, (S+16)*(S+8) = 6*S*S
$$S^2+24S+128=6S^2$$ 
$$5S^2-24S-128=0$$

Solving for S, we get S = 8 
Hence, length of rectangle = 24 cm and breadth = 16 
Perimeter of rectancgle = 80 cm

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