The sum of the square of 3 consecutive positive number is 365.the sum of the number is?

Question

Maruti Konduri · Answer

(a-1)^2 + a^2 + (a+1)^2 = 365
3a^2 + 2 = 365
Or, a = 11
So, the three numbers are 10,11 and 12 and their sum is 33

Mr. Shlongs · Answer

33

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