SNAP 2008 Question Paper

Finally, he walks in North-West direction.

Here, we have 8 corner cubes will have 3 side painted, 16 middle cubes
of each edge will have 2 sides painted, 10 middle cubes of each face
(not touching any edge) will have 1 side painted and rest will have no
side painted.

Here, we have 8 corner cubes will have 3 side painted, 16 middle cubes of each edge will have 2 sides painted, 10 middle cubes of each face (not touching any edge) will have 1 side painted and rest will have no side painted.

Total there are 36 small cubes.

So, no. of cubes with no side painted = 36-16-8-10 = 2 cubes

Here, the corner cubes of 1cm x 1cm will have 3 sides painted and the middle cubes on each edge will have 2 sides painted. On counting using the figure above, we can see there are 16 such cubes.

It is given that a+b+c=17. Also, since a is even, one of b or c must be even and the last one has to be odd.

So, Even + Even + Odd= 17.

With all distinct digits, the only value that satisfies is 8+6+3.

Given, i-f=4. Therefore the possible pairs for i and f are- (9,5), (8,4), (7,3), (6,2), (5,1).

Since, 8, 6 and 3 are already one among either a,b or c, we can eliminate those possibilities where 8,6 or 3 appears.

We are left with only two possibilities for i and f- (9,5) and (5,1).

Since, c+f+i= 14 and the no digit is equal to 0. Therefore, (9,5) gets eliminated and we get i=5, f=1 and c= 8.

a cannot be 3. So, a= 6 and b=3.

Now, 9 is not immediately below 3 and it cannot be in Column A. Hence it is in B3. 7 is in B2 and since, 4 cannot be to its left, we get the following table:

.'. 9 is in B3. 

The sequence that is followed is 4, 4*8=32, 32*9=288, 288*10=2880, 2880*11= 31680.

Let selling price per lemon of Jamuna be 'j' and that of Seema's be 's'.

Jamuna sells 2 lemons for Rs. 0.5 which makes j=(1/4)

Seema sells 3 lemons for Rs. 0.5 which makes s=(1/6)

After Seema leaves, Jamuna sells 5 lemons for a rupee and let it be denoted by t=(1/5)

Let the no. of lemons with each one of them be N.

If Seema would've sold her N lemons, she would've earned Rs. (N/6) and similarly, Jamuna would have earned Rs. (N/4).

When their individual stock is sold together, they earn Rs. (2N/5).

When counting, they observe that there's shortage of Rs. 3.50

So the eqn we can form is:

(2N/5)-(N/4)-(N/6) = 3.50

=> (N/60) = 3.5

=> N = 210 lemons

So, if Jamuna didn't sell both stocks together, she'd have earned Rs. (210/4) = Rs. 52.5

But on selling the stocks together and dividing the money equally, she gets Rs. ((2x210)/5) = Rs. 42 

$$\therefore\ $$ Jamuna suffers a loss of Rs. 10.5

Let the orange juice be in cup A initially and lemonade in B.

Let their vol. be 40L.

Let the vol. of the teaspoon be 10L.

On taking out 10L of orange juice from A and putting it in B, vol. of A becomes 30L and that of B becomes 50L.

In B, the ratio of vol. of orange juice to lemonade is 1:4.

Further when we take a teaspoon of the mixture from B, the vol. of liquid in the teaspoon will also have orange juice to lemonade in the ratio 1:4 i.e. 2L of orange juice and 8L of lemonade which is put into A.

So finally A contains 8L of lemonade and B contains 8L of orange juice because the teaspoon initially put in 10L and then took 2L out.

Education and small family norms are 2 separate parameters which can lead the nation to progress and prosperity. Big families which can afford education, can also contribute to the nation's progress. So, assumption B is not implicit.

Clearly, if we assume A, it will lead us to the conclusion stated in the question.

The most sensible words that can be formed are IMMODEST and INDECENT. Since, both are synonyms, option D is our answer.