SNAP 2007 Question Paper

SI = $$\frac{PTR}{100}$$

Given SI = 7/25P when t=4

$$\frac{7}{25}P\ =\frac{4PR}{100}$$

=> R=7

Number of days in February = 28

Number of months having three days less than 31 i.e, 28 days = 1

$$\therefore\ $$Required probability = $$\frac{1}{12}$$

Hence, the correct answer is Option D

First person: For every 2 steps he takes, the escalator moves by 3 steps at the same time.
Hence, 5 steps are covered at a time.
This is repeated 24 times(120/5).
Hence, first person takes = 24 *2 = 48 steps
Second person: For every 3 steps he takes, the escalator moves by 5 steps at the same time.
Hence, 8 steps are covered at a time.
This is repeated for 15 times(120/8)
Hence, second person takes = 3 * 15 = 45 steps
Total number of steps = 48 + 45 = 93

When arranged in ascending order, we get the noontime temperatures as:

66, 69, 70, 75, 77, 78 and 78.

m= 75.

f= 78 (occurs twice)

a= $$\ \frac{\ \left(66+69+70+75+77+78+78\right)}{7}=\ \ \frac{\ 513}{7}=73.29$$

So, a<m<f. -Option B

Lets assume the park is an equilateral triangle with side '2x' units, => the side of the flower bed = 'x' units

Area of park = $$\frac{\sqrt{\ 3}}{4}\cdot\left(2x\right)^2$$ =$$\frac{\sqrt{\ 3}}{4}\cdot4x^2$$

Area of flower bed = $$\frac{\sqrt{\ 3}}{4}\cdot x^2$$ 

Area of path = area of park -  area of flower bed = $$\frac{\sqrt{\ 3}}{4}\cdot3x^2$$

Ratio of area of path to area of flower bed = $$\frac{\left(\frac{\sqrt{\ 3}}{4}\cdot3x^2\right)}{\frac{\sqrt{\ 3}}{4}x^2}$$ = 3:1

f(x) = 3-x , if x$$\le\ $$0

$$\therefore\ $$ f(-3) = 3-(-3) = 6

By the given information,

Total number of Year III student's name= 3*100= 300

Total number of Year II student's name= 2*150= 300

Total number of Year I student's name= 1*200= 200. 

Number of favourable outcomes= year III student's name= 300 

Total Sample space= total number of names= 300+300+200= 800.

Therefore, required probability= $$\ \frac{\ 300}{800}=\ \ \frac{\ 3}{8}$$- Option D

This can be solved easily by using allegations

$$p=\frac{\left(p1q1+p2q2\right)}{q1+q2}$$

Here p = M , p1=P , p2=N

                     q1=3 , q2=6

$$\ \therefore\ M=\frac{\left(3P+6N\right)}{3+6}$$

On solving 3M = P+2N

Cubes are a 3-D figure, and so, the intersection of two 3-D figure must be a 2-D figure. 

So, Cube cannot be the intersection of two cubes.

Let the number of overtime hours logged be x.

Let the number of accidents reported be A.

So, since the relationship between A and x is linear, we can write A= ax+c

Given, when x=1000, A=8.

So, 8= 1000a+ c--------------(1)

Again, when x= 400, A=5.

So, 5= 400a+ c ----------------(2)

Subtracting Eqn 2 from 1, we get,

600a= 3

=> a= 1/200. 

Now putting this value of a in Eqn 1, we find

8= $$\ \frac{\ 1000}{200}+c$$

=>c= 8-5=3.

So, when x=0,

A= c= 3- option B