Question 88

The average of nine numbers is M and the average of three of these is P. If the average of remaining numbers is N, then

Solution

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This can be solved easily by using allegations

$$p=\frac{\left(p1q1+p2q2\right)}{q1+q2}$$

Here p = M , p1=P , p2=N

                     q1=3 , q2=6

$$\ \therefore\ M=\frac{\left(3P+6N\right)}{3+6}$$

On solving 3M = P+2N

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