Question 88
The average of nine numbers is M and the average of three of these is P. If the average of remaining numbers is N, then
Solution
This can be solved easily by using allegations
$$p=\frac{\left(p1q1+p2q2\right)}{q1+q2}$$
Here p = M , p1=P , p2=N
q1=3 , q2=6
$$\ \therefore\ M=\frac{\left(3P+6N\right)}{3+6}$$
On solving 3M = P+2N
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