SNAP 2007 Question Paper

Statement X:

Percentage of drop-outs for Managerial category in 2004 = $$\ \frac{\ 19236\ -\ 15389}{19236}\times\ 100\ \approx\ 20\%$$

Percentage of drop-outs for Managerial category in 2005 = $$\ \frac{\ 45292\ -\ 40763}{45292}\times\ 100\ \approx\ 10\%$$

Therefore, percentage of drop-outs from 2004 to 2005 has decreased. Statement X is true.

Statement Y:

Percentage of drop-outs for Managerial category in 2005 = $$\ \frac{\ 45292\ -\ 40763}{45292}\times\ 100\ \approx\ 10\%$$

Percentage of drop-outs for Technical category in 2005 = $$\ \frac{\ 63298\ -\ 60133}{63298}\times\ 100\ \approx\ 5\%$$

Percentage of drop-out is lower for Technical category.

Statement Y is false

Answer is option A.

Evaluating statement X,

In the year 2005, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 399}{40763}=0.00978$$

In the year 2005, In Technical category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 637}{60133}=0.0106$$

So, statement X is false.

Evaluating statement Y,

In the year 2005, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 399}{40763}=0.00978$$

In the year 2004, In Managerial category, the number of candidates the number of candidates shortlisted based on CV=$$\ \frac{\ 138}{15389}=0.00896$$

So, statement Y is True. Hence, Option B.

Let's evaluate statement X first.

For technical jobs in 2004, the number of candidates offered jobs as a proportion of the number of CV’s posted=$$\ \frac{\ 181}{59981}=0.00301$$

For Managerial jobs in 2004, the number of candidates offered jobs as a proportion of the number of CV’s posted=$$\ \frac{\ 48}{15389}=0.00312$$

So, statement X is false.

Evaluating Y,

In technical category in 2004, the number of candidates offered jobs as a proportion of the candidates shortlisted=$$\ \frac{\ 181}{684}=0.2646$$

In Managerial category in 2004, the number of candidates offered jobs as a proportion of the candidates shortlisted=$$\ \frac{\ 48}{138}=0.3478$$

So, statement Y is also false.

Hence, option D.

We will go by the options to check each one of them

Option A says SIFY on BSE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 247-232}{232}\cdot100\%=\ \ \frac{\ 15}{232}\cdot100\%=6.465\%$$

Option B says INFY on NQE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 10.5-9.5}{9.5}\cdot100\%=\ \ \frac{\ 1}{9.5}\cdot100\%=10.52\%$$

Option C says Wipro on NQE.

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 6.5-5.5}{5.5}\cdot100\%=\ \ \frac{\ 1}{5.5}\cdot100\%=18.18\%$$

Option D says TCS on NQE

% increase= $$\ \frac{\text{ Closing Price-Opening Price}}{\text{Opening Price}}\cdot100\%=\ \frac{\ 40-40.5}{40.5}\cdot100\%=\ \ \frac{\ -0.5}{40.5}\cdot100\%=-1.23\%$$

So, Option C shows the highest increase.

First we convert the currency of Kya Kya into Rs. by multiplying the values to 11 and we can get the following table:

In SIFY, profit made by him= $$\ \frac{\ 232-231}{231}\cdot100\%=0.43\%$$

In INFY, profit made= $$\ \frac{\ 105-104.5}{104.5}\cdot100\%=0.47\%$$

In WIPRO, profit made= $$\ \frac{\ 60.5-60}{60}\cdot100\%=0.83\%$$

In TCS, Profit made= $$\ \frac{\ 450-445.5}{445.5}\cdot100\%=1.01\%$$

Therefore, max profit is made in TCS share

Given, total shares of SIFY= 1000000

Shares purchased by SATYAM= 15% of 1000000= 150000.

Now, 50% of the shares were purchased at BSE's opening price i.e. Rs. 232 and 50% of the shares were purchased at BSE's closing price, Rs. 247.

So, total amount paid by SATYAM= 75000*(232)+ 75000(247)= Rs. 75000(479)= Rs. 35925000 which is close to Rs. 36 millions.

Average Salary in Administration = $$\ \frac{\ Total\ Salary\ }{Total\ number\ of\ People}$$

Total number of people on Administration = $$22\%\ of\ 18,000\ =\ 3,960$$

Hence $$12,000\ =\ \frac{\ Total\ Salary}{3,960}$$

Total Salary = $$12,000\times\ 3960\ =\ 47520000$$ = $$4.7\ crores$$

No of the employees in Sales & Marketing in 2005 = $$18\%\ of\ 18,000\ =\ 3240$$

No of the employees in Sales & Marketing in 2006 = $$20\%\ of\ 20,000\ =\ 4000$$

Percent Increase = $$\ \frac{\ 4000-3240}{3240}\times\ 100\%\ =\ 23.45\%$$

From above chart we can get the following table.

Variation of A = |4800-3960| = 840

Variation of B = |5200-4140 | = 1060

Variation of C = |4000-3240 | = 760

Variation of D = | 4000 - 5220 | = 1220

Variation of E = |2000-1440| =560

D has max variation

From the above charts, the following table can be made.

Let $$N$$ be the number of people who joined in 2006 in Operations department, then 

$$\ 4140-300+N\ =5200$$

$$N\ =1360$$