NICL Assistant Online Exam 2015 Question paper

Each number is multiplied by 2 and then 10 is added.

2 $$\times 2 + 10$$ = 14

14 $$\times 2 + 10$$ = 38

38 $$\times 2 + 10$$ = 86

86 $$\times 2 + 10$$ = 182

182 $$\times 2 + 10$$ = 374

The pattern followed is :

10 $$\times 2 + 8$$ = 28

28 $$\times 2 + 7$$ = 63

63 $$\times 2 + 6$$ = 132

132 $$\times 2 + 5$$ = 269

269 $$\times 2 + 4$$ = 542

Let principal amount in both schemes = $$Rs. P$$

In scheme A, time = 4 years and rate = 8% under simple interest.

=> $$S.I. = \frac{P \times R \times T}{100}$$

=> $$8384 = \frac{P \times 8 \times 4}{100}$$

=> $$P = \frac{8384 \times 100}{32} = Rs. 26,200$$

In scheme B, time = 6 years and amount received under simple interest = Rs. 39,562

Principal amount = Rs. 26,200

Interest = 39562 - 26200 = Rs. 13,362

Let rate of interest = $$r \%$$

=> $$S.I. = \frac{P \times R \times T}{100}$$

=> $$13362 = \frac{26200 \times r \times 6}{100}$$

=> $$r = \frac{13362}{262 \times 6} = \frac{51}{6}$$

=> $$r = 8.5 \%$$

Quantity of pure milk in the vessel = 80 litres

After 16 litres of milk is taken out, and replaced with water

=> Milk left = 80 - 16 = 64 litres

Water left = 16 litres

Now, if 16 litres of mixture is taken out, i.e. $$(\frac{1}{5})^{th}$$ of the mixture

=> Milk left = $$64 - \frac{1}{5} \times 64 = 51.2$$ litres

Water left = $$16 - \frac{1}{5} \times 16 = 12.8$$ litres

Now, 24 litres of water is added, quantity of milk will remain unaffected.

=> Milk = 51.2 litres

Water = 12.8 + 24 = 36.8 litres

$$\therefore$$ Ratio = 51.2 : 36.8 = 32 : 23

Pihu's monthly income = Rs. 39,500

Income spent on household expenditures = $$\frac{9}{20} \times 39500$$

= $$9 \times 1975 = Rs. 17,775$$

Amount spent on school fees = $$\frac{24}{100} \times 39500$$

= $$24 \times 395 = Rs. 9,480$$

Income left = 39500 - 17775 - 9480 = Rs. 12,245

Now, % amount donated to NGO = 40%

Thus, amount left = $$\frac{60}{100} \times 12245 = Rs. 7,347$$

Using : $$M_1 D_1 = M_2 D_2$$

Let $$x$$ men finish the work in 84 days

=> $$(x + 6)$$ workers finish the work in 72 days

=> $$M_1 = x , D_1 = 84$$ and $$D_2 = 72$$

=> $$x \times 84 = (x + 6) \times 72$$

=> $$x \times 7 = (x + 6) \times 6$$

=> $$7x = 6x + 36$$

=> $$7x - 6x = x = 36$$

Let marked price of 1 kg rice = $$Rs. 10$$

=> Marked price of 30 kg rice = $$30 \times 10 = Rs. 300$$

Discount % = 20%

Thus, cost price of retaailer = $$\frac{80}{100} \times 300 = Rs. 240$$

Additionally, he got 8 kg rice for free and he sells at original marked price.

Thus, selling price of 38 kg rice = $$38 \times 10 = Rs. 380$$

$$\therefore$$ Profit % = $$\frac{380 - 240}{240} \times 100$$

= $$\frac{175}{3} = 58\frac{1}{3}\%$$

x is greater than y by 12 and the respective ratio, between x and y is 3 : 2

=> $$x - y = 12$$ => $$x = 12 + y$$

Also, $$\frac{x}{y} = \frac{3}{2}$$

=> $$\frac{12 + y}{y} = \frac{3}{2}$$

=> $$24 + 2y = 3y$$

=> $$3y - 2y = y = 24$$

=> $$x = 12 + 24 = 36$$

Now, $$z = \frac{1}{3} \times y$$

=> $$z = \frac{1}{3} \times 24 = 8$$

$$\therefore z + x = 8 + 36 = 44$$

Let the amount invested in scheme B = $$Rs. x$$

=> Amount invested in scheme A = $$Rs. (8,000 - x)$$

The rate of interest of scheme A and B are 10 p.c.p.a. and 20 p.c.p.a. respectively

Also, amount under C.I. = $$P (1 + \frac{R}{100})^T$$

=> $$[x (1 + \frac{10}{100})^2] + [(8000 - x) (1 + \frac{20}{100})^2] = 10,600$$

=> $$x (\frac{11}{10})^2 + (8000 - x) (\frac{6}{5})^2 = 10600$$

=> $$\frac{121 x}{100} + 11520 - \frac{36 x}{25} = 10600$$

=> $$\frac{23 x}{100} = 11520 - 10600 = 920$$

=> $$x = 920 \times \frac{100}{23} = 40 \times 100$$

=> $$x = Rs. 4,000$$

Avinash's present age = $$54$$ years

=> Shashi's present age = $$\frac{5}{9} \times 54 = 30$$ years

Let $$x$$ years ago, respective ratio of their ages = $$7 : 3$$

=> $$\frac{54 - x}{30 - x} = \frac{7}{3}$$

=> $$162 - 3x = 210 - 7x$$

=> $$4x = 210 - 62 = 48$$

=> $$x = \frac{48}{4} = 12$$ years