MAH MBA CET Sample Paper 2025

Tank filled in an hour when all of them are working simultaneously = 1/3 + 1/6 - 1/9 = 7/18
Hence time taken to fill up the tank = 18/7 h

Let the volume of the tank = V
Let the efficiency of the tap A = V/A = V/6
And efficiency of the tap B = V/B = V/8
Efficiency of tap C to empty the tank = V/C = V/12
Let T be the total time taken by the system to fill the tank.
T*(V/6 + V/8 - V/ 12) = V
==> T = 24/5 = 4.8 hours.
So the correct option to choose is B - 4.8 hours.

Let the total work be 200 units.
A’s rate of work = 200 units/10 days = 20 units per day
B’s rate of work = 200 units/20 days = 10 units per day
So, work done by A and B together in 4 days = (20+10)*4 = 120 units
Work left = 200 - 120 = 80 units
Time taken by B to complete the remaining work = 80 units/10 units per day = 8 days

Let the distance between A and B be D.

Time taken = D/58 + D/52 = 110*D/(58*52)

So, average speed for the whole journey = 2D/Time = 58*52*2D/110D = 54.8363636 kmph = 55kmph approximately

Average speed = (Total Distance travelled)/(Total time taken)
= (100+200)/(100/25 + 200/40) = 300/(4+5) = 100/3 = 33.33km/hr

Relative speed of train A with respect to B = 5 km/h
Distance to be covered = 200 km
Time taken = $$\frac{200}{5}$$ = 40 h

Let the speed of the first train be v m/s
Then
400/10 = v
=> v = 40 m/s
Now the speed of the second train = 72 km/hr = 20 m/s
Since both the trains are running in the same direction, the relative speed between the two trains is 40 - 20 = 20 m/s
Distance to be covered = 400 + 300 = 700m
Hence the required time = 700/20 = 35 seconds.

The average = 24. So, the numbers are 24 - 3, 24 - 1, 24 + 1 and 24 + 3.
ie. 21, 23, 25, 27
So, the sum of squares = $$21^2 + 27^2 = 441+729 = 1170$$
Hence, the average is $$1170/2 = 585$$

Let the number of students in the two sections be 3k and 4k.
Total weight of the class = 3k * 40 + 4k * 42 = 120k + 168k = 288k
So, average weight of the class = 288k/(3k + 4k) = 288/7 = 41.14 kg

Average monthly investment made by Ram = $$\dfrac{60000*6 + 20000*6}{12}$$ = Rs. 40000
Average monthly investment made by Shyam = Rs. 40000
Hence Ram’s share = $$\dfrac{40000}{40000+40000}\times 6000$$ = Rs. 3000
Therefore, we can say that option E is the correct answer.