MAH MBA CET Sample Paper 2025

When the given box would be folded, Opposite face sets would be (1) Star and Arrow ,(2) Dot and Square ,(3) Triangle and Circle

(B) Dot and Star would be on adjacent faces

(C) Circle and Arrow would be on adjacent faces

(D) Triangle and Dot would be on adjacent face

Hence, Option A is the Correct answer

For the images represented in options A, B, D, E the second figure inside the square is generated when the first figure is rotated by 90 degrees in the clockwise direction. The same is not true for option C.

All other options other than option D have their digits adding up to 15. 

In D, we have the question figure which is shown in red colour in the figure below -  

Hence, option D is the right choice.

We have,
7 % 6 h $ & 2 d s ) ! 8 # 5 p a 3 * c ? 1 b \ e
% 6 and h are three consecutive characters with the last character ‘h’ in between the other 2.
Next character ‘&’ is two places to the right of ‘h’. Further same logic continues.
)8! Are consecutive character and ‘5’ comes two places to the right of ‘8’. Thus, ‘5’ must be next in the given sequence.
Hence, option A is the correct choice.

In the word " SEMBLANCE " the pairs having as many letters between the words as they have in the English alphabet series are :

AE - 3 letters.

LN - 1 letter.

AC - 1 letter.

A total of 3 possible pairs.

The letters that can be used are: " P, E, N, T, O ".

The possible words that can be formed include:  " PEN ", " PET ", " NET ", " PENT ", " TEN ", " OPEN ", " PEON ",  " POET ", " NOTE ",....

When the alphabets of the word RECOGNITION are arranged from left to right in an orderly fashion :

The order is given by :  CEGIINNOORT.

The alphabet with index value 4 = O.

The alphabet with index value 7 = I.

The number of alphabets in between is: 5

Hence option E is the answer.

In the word MODULAR the possible pairs of letters that satisfy the condition that each of which has as many letters between them in the word as they have in between English alphabetical series :

The possible pairs of letters are :

" O - L ".

" A - D ".

" R - U ". 

The possible words which can be generated using the words :

"B", "U", "R", "T", "E".

BUT,  TUBE, BRUTE, RUT,  TRUE, TUB, BET, RUB .....................

Hence the answer is greater than six.