MAH MBA CET Sample Paper 2026

Assume that the capacity of the tank is $$x$$ litres, the efficiency of an inlet pipe is $$y$$ litres per hour, and that of an outlet pipe is $$z$$ litres per hour.

So, given that an inlet pipe can fill an empty tank in 12 hours or, 

$$\dfrac{x}{y}=12$$

$$y=\dfrac{x}{12}$$ . . . (1)

Also, given that an outlet pipe can drain a filled tank in 10 hours or,

$$\dfrac{x}{z}=10$$

$$z=\dfrac{x}{10}$$ . . . (2)

Now, all the pipes are opened together to an empty tank,

so the time taken to fill the tank is $$\dfrac{x}{3y-2z}$$

Putting the values of $$y$$ and $$z$$ from equations (1) and (2) we get

Time taken = $$\dfrac{x}{3y-2z}=\dfrac{x}{\dfrac{3x}{12}-\dfrac{2x}{10}}=20$$ hours

Hence, the answer is 20 hours.

It is said that the task was finished in 15 days, so if we assume that one man does one unit of work each day, the amount of work done by the men after n days can be found by the formula, $$\frac{n\left(n+1\right)}{2}$$

It is given that it takes them 15 days, substituting 15 for n in that formula, we get 120 units of work. 

Now these 120 units are work done by men, it is given that women are 40% less efficient, that means $$0.4\left(M\right)=W$$
The same 120 units of men's work are equivalent to $$\frac{120}{0.4}=300\ units$$ of Women's work. 

From the options we see, 24 days, which will equal $$\frac{24\left(25\right)}{2}=300$$
Hence, the answer is 24. 

Let the total work to be done is 300 units.

So, P does = 300/10 = 30 units per day

Q does = 300/15 = 20 units per day,

R does = 300/20 = 15 units per day.

P and Q start working on the take and worked for 3 days. So the work done in 3 days = (30 + 20)*3 = 150 units.

Now, R joins and P left. So, the work done by R and Q in the next 3 days = (20 + 15)*3 = 105 units

Remaining work = 300 - 150 - 105 = 45 units

Fraction of the work remaining = 45/300 = 3/20

Let us assume the speeds of Raju and Ravi as kx, ky.

The ratio of their speeds are x:y.

x+y = 11

x-y = 5

x = 8, y=3

We are given that Raju travels 1200m in 15 sec. His speed will be 80 m/s.

kx = 80 => k = 10.

The speed of Ravi is 30m/s. 

Time Ravi takes to travel 1200m will be 40s.

Anuj took 4 hours after meeting Bharat. Hence, Anuj met Bhrat after 6 hours. 

The time before their meeting can be calculated as $$\sqrt{\ t_1t_2}$$, where $$t_1$$ and $$t_2$$ are time taken by the two people to cover the remaining distance after crossing each other. 

We get the equation $$6=\sqrt{\ 4t_B}$$
$$36=4t_B$$
$$t_B=9$$

Hence, it took Bharat 9 more hours after meeting Anuj to complete his journey and reach P. 

This, in addition to the 6 hours before meeting Anuj, gives the total time taken by Bharat to be 15 hours. 

Therefore, Option D is the correct answer. 

Let the speed of the train be ‘v’ m/s and it’s length be ‘l’

Then
l/v = 20
20v = l
Also,
(l + 1000)/v = 100
=> 100v = 1000 + l
=> Solving both the equations, we get
v = 12.5 m/s and l = 250 m
Hence the length of the train is 250 m and speed = 12.5 m/s

In the first half an hour, the slower train covers some distance, which is 

$$80\times\dfrac{30}{60}=40\ $$ km

Hence, now the distance between the two trains is $$940-40\ =900$$ km.

The time after which both trains meet is $$\dfrac{900}{80+100}=\dfrac{900}{180}=5$$ hrs

Hence, the distance travelled in this time by the slower train will be $$5\times80=400$$ km

But it also covered 40 km before this, so the total distance travelled is 40+400 = 440 km.

Hence, the answer is 440 km.

Let's say the contents of the barrel is X litres, and 10% is being taken out and being replaced every operation,
That means there's 90% of the barrel's contents intact after every operation. 

So, if we start off with X litres of single malt whiskey, after the first operation we will have 0.9X of single malt whiskey,
And after n operations the contents of single malt whiskey will be $$0.9^nX$$

And we want this value to be lesser than 0.65X

After 4 operations the content will be 0.6561X

So, a minimum of 5 operations must be performed

Let the average of all the sisters before the birth of the pair of twins is X.

So, the sum of their ages = 6X

When the pair of twins born, the sum of their ages would remain the same.

Hence, the average of their ages when the pair of twins born = 6X/8 or 3X/4

So, the average decreased by 12 i.e. X - 3X/4 = 12

X/4 = 12

Or, X = 48

Therefore, the sum of their ages when the pair of twins born = 6*48 = 288

Let the volume of BE be 8m and volume of RE be 5n.

The concentration of alcohol in the mixture is $$\frac{\left(3m+4n\right)}{\left(8m+5n\right)}=\frac{1}{2}$$

6m+8n = 8m+5n

3n = 2m

m:n = 3:2

We need 8m:5n = $$\frac{8}{5}\cdot\frac{3}{2}\ =\frac{12}{5}$$