IIFT 2018 Question Paper

From the above table it is clear that option D is the correct answer.

From the table it can be seen that East Asia is closest to the GNI of the world

Combined GNI of India and US is 21410.

GNI of world is 78000.

Percentage = (21410/78000)*100

=27.45%

South Asia has third lowest difference between PPP per capita and GNI per capita.

The answer is option B.

Required percentage = $$\ \ \ \frac{\ 24+16+12+6+6+4.5+2+0+0+0}{495.17}\times\ 100=\frac{70.5}{495.17}\times\ 100=14.23\%$$
The answer is option B.

From the graph, the total revenue of Hilton worldwide is 12 billion dollars.

We are told that the room rent per day = 365 USD

Let the total number of rooms available be 'T'. We are also told that occupancy is 70%. So, the occupied rooms on any day are $$\frac{70}{100}T$$  

$$\frac{70}{100}T\times\ 365\times\ 350=12\times\ 10^9$$

Solving, we get T = 134,190

In thousands, it will be 134.

The closest option is option B. Hence, the answer is option B.

Let the rooms available in different regions be x, 2x, 5x and 4x. The occupancy rates in the 4 different regions in the Quarter 1 are given as 67, 60, 61 and 64. The average occupancy rate can be calculated as,

Average occupancy rate = $$\ \ \dfrac{\ 67\left(x\right)+60\left(2x\right)+61\left(5x\right)+64\left(4x\right)}{x\ +\ 2x\ +\ 5x\ +\ 4x}=\dfrac{748x}{12x}=62.3$$

The answer is option A.

Average annual occupancy rate of Asia Pacific = $$\ \frac{\ 67+68+72+71}{4}=\frac{278}{4}=69.5$$
Average annual occupancy rate of America = $$\ \frac{\ 60+69+61+71}{4}=\frac{261}{4}=65.25$$
Average annual occupancy rate of Europe = $$\ \frac{\ 74+69+61+78}{4}=\frac{282}{4}=70.5$$
Average annual occupancy rate of Middle East and Africa = $$\ \frac{\ 64+58+61+63}{4}=\frac{246}{4}=61.5$$
Increasing order - Middle East and Africa, America, Asia Pacific and Europe
The answer is option B.

Total revenue in 2017 = 34280 + 18450 + 16350 + 8190 + 1700 + 170 = 79140
Angle subtended by GBS = $$\frac{16350}{79140}\times\ 360^{\circ\ }$$ = 74.37 $$\approx\ $$ 75
The answer is option A.

TSCP - 35140 + 35240 + 34280 = 104760
CS - 17840 + 18190 + 18450 = 54480
GBS - 18220 + 19280 + 18570 + 18400 + 17800 + 17160 + 16700 + 16350 = 142480 - 2nd
SYS - 9550 + 7710 + 8190 = 25450
GF - 2240 + 2100 + 2010 + 2020 + 2000 + 1840 + 1690 +1700 = 15600
Others - least - 3710
SOFT - 22490 + 24940 + 25450 + 25930 + 25400 = 124210 - 3rd
GTS - 38200 + 40880 + 40240 + 38550 + 37100 = 194970 - 1st
S&T - 17970 + 18990 + 17670 + 14370 + 10000 = 79000
Software has earned third highest cumulative revenue in the time period 2010-2017.
The answer is option B.

Revenue in 2012 = 18570 + 2010 + 580 +  25450 + 40240 + 17670 = 104520 = 104.52 billion
Profit % = $$\frac{49}{104.52-49}\times\ 100\ =\ 88.26\%\ $$
Let the profit made by Systems and Technology in 2012 be 'x'
$$\frac{x}{17670-x}=\frac{49}{55.52}$$
x = 8283.87
The answer is option A.

Difference = $$\ \ \frac{\ 18190-16700}{79920}\times\ 100\ =\ 1.86\%\ \approx\ 2\%$$
The answer is option B.

Austria - 3.71 + 4.18 + 3.88 + 4.08 + 4.09 + 4.25 = 24.19
UK - 3.77 + 4.03 + 3.67 + 4.05 + 4.11 + 4.33 = 23.96
USA - 3.78 + 4.05 + 3.51 + 3.87 + 4.09 + 4.08 = 23.38
Switzerland - 3.63 + 4.02 + 3.51 + 3.97 + 4.1 + 4.24 = 23.47
France - 3.59 + 4 + 3.55 + 3.84 + 4 + 4.15 = 23.13
Increasing order - France, USA, Switzerland, UK, Austria
The answer is option C.

Austria - 4.25 - 4.08 = 0.17
UK - 4.33 - 4.05 = 0.28
USA - 4.08 - 3.87 = 0.21
Switzerland - 4.24 - 3.97 = 0.27
France - 4.15 - 3.84 = 0.31
Ascending order - Austria, USA, Switzerland, UK and France
The answer is option A.

Difference is minimum in the year 2016. The answer is option A.

Customs - 2.96 - 2.69 = 0.27
International Shipments - 3.21 - 3.08 = 0.13
Timeliness - 3.5 - 3.47 = 0.03
Tracking & Tracing - 3.32 - 3.03 = 0.29
The answer is option C.

Growth rate of emoluments per worker is highest in the year 2009-10.

The answer is option A.

Fixed capital per factory is lowest in the year 2011-12.

The answer is option B.

Material as a proportion of 'Total inputs' is highest in the year 2009-10.

The answer is option B.

Annual percentage growth in fixed capital is greater than annual percentage growth in number of factories for four years, i.e. 2011-12, 2013-14, 2014-15 and 2015-16.

The answer is option B.

43 + 20 = 63, 63/7 = 9
352 + 103 = 455, 455/7 = 65
75 + 23 = 98, 98/7 = 14
115 + 67 = 182, 182/7 = 26
53 + 24 = 77, 77/7 = 11
$$\ \frac{\ 79+X}{7}=54$$
X = 299
The answer is option A.

In statement 1, it is given that Albert participates in job fair on Monday. In statement 7, it is given that Daisy stays in Marriott and attends the conference on the last day of the week. This implies Daisy attends conference on Saturday. In statement 1, it is given that the person who works in Whirlpool participates in the Job fair on Saturday. Therefore,

In statement 3, it is given that Betty and Daisy participate in the Job fair on consecutive days. This implies Betty participate in the Job fair on Friday. In statement 5, it is given that the person working with Oppo participates in the Job fair on Friday. This implies Betty is working with Oppo. Therefore,

In statement 2, it is given that Fred does not stay in Hyatt but works in Himalaya. In statement 6, it is given that Claire who is working with Nestle participates in the Job fair at a gap of one day prior to Evan. This implies Claire attends job fair on Tuesday and Evan attends job fair on Thursday. 

In statement 8, it is given that the person working with Apple stays in Radisson. In statement 4, it is given that Claire participates in the Job fair on the day before the person staying in Crowne Plaza but on the next day of Pepsi employee. This implies the person staying in Crowne Plaza attends job fair on Wednesday and Pepsi employee attend job fair on Monday. 

Final arrangement:

Evan is working with Apple. The answer is option C.

In statement 1, it is given that Albert participates in job fair on Monday. In statement 7, it is given that Daisy stays in Marriott and attends the conference on the last day of the week. This implies Daisy attends conference on Saturday. In statement 1, it is given that the person who works in Whirlpool participates in the Job fair on Saturday. Therefore,

In statement 3, it is given that Betty and Daisy participate in the Job fair on consecutive days. This implies Betty participate in the Job fair on Friday. In statement 5, it is given that the person working with Oppo participates in the Job fair on Friday. This implies Betty is working with Oppo. Therefore,

In statement 2, it is given that Fred does not stay in Hyatt but works in Himalaya. In statement 6, it is given that Claire who is working with Nestle participates in the Job fair at a gap of one day prior to Evan. This implies Claire attends job fair on Tuesday and Evan attends job fair on Thursday.

In statement 8, it is given that the person working with Apple stays in Radisson. In statement 4, it is given that Claire participates in the Job fair on the day before the person staying in Crowne Plaza but on the next day of Pepsi employee. This implies the person staying in Crowne Plaza attends job fair on Wednesday and Pepsi employee attend job fair on Monday.

Final arrangement:

Fred participated in the job fair on Wednesday. The answer is option C.

In statement 1, it is given that Albert participates in job fair on Monday. In statement 7, it is given that Daisy stays in Marriott and attends the conference on the last day of the week. This implies Daisy attends conference on Saturday. In statement 1, it is given that the person who works in Whirlpool participates in the Job fair on Saturday. Therefore,

In statement 3, it is given that Betty and Daisy participate in the Job fair on consecutive days. This implies Betty participate in the Job fair on Friday. In statement 5, it is given that the person working with Oppo participates in the Job fair on Friday. This implies Betty is working with Oppo. Therefore,

In statement 2, it is given that Fred does not stay in Hyatt but works in Himalaya. In statement 6, it is given that Claire who is working with Nestle participates in the Job fair at a gap of one day prior to Evan. This implies Claire attends job fair on Tuesday and Evan attends job fair on Thursday.

In statement 8, it is given that the person working with Apple stays in Radisson. In statement 4, it is given that Claire participates in the Job fair on the day before the person staying in Crowne Plaza but on the next day of Pepsi employee. This implies the person staying in Crowne Plaza attends job fair on Wednesday and Pepsi employee attend job fair on Monday.

Final arrangement:

Average annual package of Albert, Betty and Fred = $$\ \frac{\ 40+50+60}{3}=50$$lakhs
The answer is option D.

In statement 1, it is given that Albert participates in job fair on Monday. In statement 7, it is given that Daisy stays in Marriott and attends the conference on the last day of the week. This implies Daisy attends conference on Saturday. In statement 1, it is given that the person who works in Whirlpool participates in the Job fair on Saturday. Therefore,

In statement 3, it is given that Betty and Daisy participate in the Job fair on consecutive days. This implies Betty participate in the Job fair on Friday. In statement 5, it is given that the person working with Oppo participates in the Job fair on Friday. This implies Betty is working with Oppo. Therefore,

In statement 2, it is given that Fred does not stay in Hyatt but works in Himalaya. In statement 6, it is given that Claire who is working with Nestle participates in the Job fair at a gap of one day prior to Evan. This implies Claire attends job fair on Tuesday and Evan attends job fair on Thursday.

In statement 8, it is given that the person working with Apple stays in Radisson. In statement 4, it is given that Claire participates in the Job fair on the day before the person staying in Crowne Plaza but on the next day of Pepsi employee. This implies the person staying in Crowne Plaza attends job fair on Wednesday and Pepsi employee attend job fair on Monday.

Final arrangement:

Claire is staying in Hilton. The answer is option B.

(i) S -> Purple
P,R,N -> Purple (or) P,R,N -> Blue
(ii) P -> Purple
S -> Blue  N,R -> Purple (or) S -> Purple N,R -> Blue
(iii) N -> Blue
P,R,S -> Purple (or) P,R,S -> Blue
(iv) R -> Blue
S,P -> Blue N -> Purple (or) S,P -> Purple N -> Blue
Let us consider N is in blue, then P, R, and S should be either in blue or purple. 
If N is in blue and (P,R,S) is in blue, then this doesn't satisfy the condition in statement 4. If N is in blue and (P,R,S) is in purple, then this violates statement 2. Therefore, N cannot be in blue and stays in Purple room.
Let us consider S is in purple, then P, R, and N should in purple as N cannot be in blue.
If S is in purple and (P,R,N) is in purple, then this violates statement 2. Therefore, S cannot be in purple and stays in Blue room.
Possible arrangements are:
1. P - purple, S - blue, (N,R) - purple
2. R - blue, (S,P) - blue, N - purple
Rooms of N and S are unchanged in all the cases.
The answer is option C.

(i) S -> Purple
P,R,N -> Purple (or) P,R,N -> Blue
(ii) P -> Purple
S -> Blue N,R -> Purple (or) S -> Purple N,R -> Blue
(iii) N -> Blue
P,R,S -> Purple (or) P,R,S -> Blue
(iv) R -> Blue
S,P -> Blue N -> Purple (or) S,P -> Purple N -> Blue
Let us consider N is in blue, then P, R, and S should be either in blue or purple.
If N is in blue and (P,R,S) is in blue, then this doesn't satisfy the condition in statement 4. If N is in blue and (P,R,S) is in purple, then this violates statement 2. Therefore, N cannot be in blue and stays in Purple room.
Let us consider S is in purple, then P, R, and N should in purple as N cannot be in blue.
If S is in purple and (P,R,N) is in purple, then this violates statement 2. Therefore, S cannot be in purple and stays in Blue room.
Possible arrangements are:
1. P - purple, S - blue, (N,R) - purple
2. R - blue, (S,P) - blue, N - purple
If Richie chose to stay in the room painted blue, then Pinky stays in blue painted room. 
The answer is option B.

(i) S -> Purple
P,R,N -> Purple (or) P,R,N -> Blue
(ii) P -> Purple
S -> Blue N,R -> Purple (or) S -> Purple N,R -> Blue
(iii) N -> Blue
P,R,S -> Purple (or) P,R,S -> Blue
(iv) R -> Blue
S,P -> Blue N -> Purple (or) S,P -> Purple N -> Blue
Let us consider N is in blue, then P, R, and S should be either in blue or purple.
If N is in blue and (P,R,S) is in blue, then this doesn't satisfy the condition in statement 4. If N is in blue and (P,R,S) is in purple, then this violates statement 2. Therefore, N cannot be in blue and stays in Purple room.
Let us consider S is in purple, then P, R, and N should in purple as N cannot be in blue.
If S is in purple and (P,R,N) is in purple, then this violates statement 2. Therefore, S cannot be in purple and stays in Blue room.
Possible arrangements are:
1. P - purple, S - blue, (N,R) - purple
2. R - blue, (S,P) - blue, N - purple
If Pinky does not like to stay in the blue painted room, then Sunny will stay in blue painted room.
The answer is option A.

In statement 2 it is given that Roses is to the immediate left of Beauty and Mineral is immediately above Roses.

In statement 4 it is given that Ferry is separated from Helping horizontally by only one word Logical.

In statement 6 it is given that Crude and Doctor are in the same horizontal row and Crude is to the right of Doctor. They can be arranged in three ways in a horizontal row.

It is given that Arguments is at $$2\times\ 3$$ position. 

There are three cases possible. Mineral, roses and beauty placed at positions (a,b,c), (d,e,f) and (p,f,r).

Case 1: Mineral, roses and beauty at (d,e,f)

In statement 1 it is mentioned that the words in $$2\times1$$ and $$3\times1$$ have the same number of letters. Mineral has 7 letters. There are no remaining words with 7 letters. Therefore, this case is not possible.

Case 2: Mineral, roses and beauty at (p,f,r)

Doctor must be placed at either $$2\times1$$ or $$3\times1$$. Doctor is a 6 letter word and there is no word with 6 letters to be placed at the alternate position. Therefore, this case is not possible.

Case 3: Mineral, roses and beauty at (a,b,c)
Placing ferry, helping and logical in fourth row will not give valid arrangement. Therefore,

Remaining words are cats, doctor, crude, mouse and scare.
The number of letters in  $$4\times3$$ should be less than  $$1\times2$$. Doctor cannot be placed in row 1. Therefore, a five letter word is placed at $$1\times2$$ and four letter word placed at $$4\times3$$.
Final arrangement:

The only possible position whose product is 8 is $$4\times\ 2$$. The word at $$4\times\ 2$$ is crude.
The answer is option A.

In statement 2 it is given that Roses is to the immediate left of Beauty and Mineral is immediately above Roses.

In statement 4 it is given that Ferry is separated from Helping horizontally by only one word Logical.

In statement 6 it is given that Crude and Doctor are in the same horizontal row and Crude is to the right of Doctor. They can be arranged in three ways in a horizontal row.

It is given that Arguments is at $$2\times\ 3$$ position.

There are three cases possible. Mineral, roses and beauty placed at positions (a,b,c), (d,e,f) and (p,f,r).

Case 1: Mineral, roses and beauty at (d,e,f)

In statement 1 it is mentioned that the words in $$2\times1$$ and $$3\times1$$ have the same number of letters. Mineral has 7 letters. There are no remaining words with 7 letters. Therefore, this case is not possible.

Case 2: Mineral, roses and beauty at (p,f,r)

Doctor must be placed at either $$2\times1$$ or $$3\times1$$. Doctor is a 6 letter word and there is no word with 6 letters to be placed at the alternate position. Therefore, this case is not possible.

Case 3: Mineral, roses and beauty at (a,b,c)
Placing ferry, helping and logical in fourth row will not give valid arrangement. Therefore,

Remaining words are cats, doctor, crude, mouse and scare.
The number of letters in $$4\times3$$ should be less than $$1\times2$$. Doctor cannot be placed in row 1. Therefore, a five letter word is placed at $$1\times2$$ and four letter word placed at $$4\times3$$.
Final arrangement:

Row 1 - 7 + 5 + 5 = 17
Row 2 - 5 + 6 + 9 = 20
Row 3 - 5 + 7 + 7 = 19
Row 4 - 6 + 5 + 4 = 15
The answer is option C.

In statement 2 it is given that Roses is to the immediate left of Beauty and Mineral is immediately above Roses.

In statement 4 it is given that Ferry is separated from Helping horizontally by only one word Logical.

In statement 6 it is given that Crude and Doctor are in the same horizontal row and Crude is to the right of Doctor. They can be arranged in three ways in a horizontal row.

It is given that Arguments is at $$2\times\ 3$$ position.

There are three cases possible. Mineral, roses and beauty placed at positions (a,b,c), (d,e,f) and (p,f,r).

Case 1: Mineral, roses and beauty at (d,e,f)

In statement 1 it is mentioned that the words in $$2\times1$$ and $$3\times1$$ have the same number of letters. Mineral has 7 letters. There are no remaining words with 7 letters. Therefore, this case is not possible.

Case 2: Mineral, roses and beauty at (p,f,r)

Doctor must be placed at either $$2\times1$$ or $$3\times1$$. Doctor is a 6 letter word and there is no word with 6 letters to be placed at the alternate position. Therefore, this case is not possible.

Case 3: Mineral, roses and beauty at (a,b,c)
Placing ferry, helping and logical in fourth row will not give valid arrangement. Therefore,

Remaining words are cats, doctor, crude, mouse and scare.
The number of letters in $$4\times3$$ should be less than $$1\times2$$. Doctor cannot be placed in row 1. Therefore, a five letter word is placed at $$1\times2$$ and four letter word placed at $$4\times3$$.
Final arrangement:

The word represented in $$4\times3$$ is cats.
The answer is option C.

In statement 2 it is given that Roses is to the immediate left of Beauty and Mineral is immediately above Roses.

In statement 4 it is given that Ferry is separated from Helping horizontally by only one word Logical.

In statement 6 it is given that Crude and Doctor are in the same horizontal row and Crude is to the right of Doctor. They can be arranged in three ways in a horizontal row.

It is given that Arguments is at $$2\times\ 3$$ position.

There are three cases possible. Mineral, roses and beauty placed at positions (a,b,c), (d,e,f) and (p,f,r).

Case 1: Mineral, roses and beauty at (d,e,f)

In statement 1 it is mentioned that the words in $$2\times1$$ and $$3\times1$$ have the same number of letters. Mineral has 7 letters. There are no remaining words with 7 letters. Therefore, this case is not possible.

Case 2: Mineral, roses and beauty at (p,f,r)

Doctor must be placed at either $$2\times1$$ or $$3\times1$$. Doctor is a 6 letter word and there is no word with 6 letters to be placed at the alternate position. Therefore, this case is not possible.

Case 3: Mineral, roses and beauty at (a,b,c)
Placing ferry, helping and logical in fourth row will not give valid arrangement. Therefore,

Remaining words are cats, doctor, crude, mouse and scare.
The number of letters in $$4\times3$$ should be less than $$1\times2$$. Doctor cannot be placed in row 1. Therefore, a five letter word is placed at $$1\times2$$ and four letter word placed at $$4\times3$$.
Final arrangement:

Beauty and scare are placed diagonally in-the matrix. The answer is option C.

In statement (1) is is given that P is sitting to the immediate left of S and the officer opposite to S discusses issues pertaining to Remedies and in statement (7) it is given that P's issue was ranked 4th and he was discussing issues related to Tariffs and sits opposite to the officer ranked 5th who represents issues related to Subsidies. Therefore,

In statement 5 it is given that the officer discussing issues related to Trade in Services is sitting opposite to T. T is sitting at a gap of one place from P and in statement 8 it is given that the officers representing issues related to Trade in Services and Trade facilitation are sitting adjacent to each other. The only possible arrangement considering statement 6 as well is as shown below.

In statement 2 it is given that U's issue is ranked 7th and there is one officer between U and the officer whose issue is ranked 2nd, and in statement 3 it is given that the officer whose issue is ranked 1 is not opposite to the officer whose issue is ranked 8 who represents issues related to Investments. 

Final arrangement:

U discusses Remedies and the rank is 7.
The answer is option C.

In statement (1) is is given that P is sitting to the immediate left of S and the officer opposite to S discusses issues pertaining to Remedies and in statement (7) it is given that P's issue was ranked 4th and he was discussing issues related to Tariffs and sits opposite to the officer ranked 5th who represents issues related to Subsidies. Therefore,

In statement 5 it is given that the officer discussing issues related to Trade in Services is sitting opposite to T. T is sitting at a gap of one place from P and in statement 8 it is given that the officers representing issues related to Trade in Services and Trade facilitation are sitting adjacent to each other. The only possible arrangement considering statement 6 as well is as shown below.

In statement 2 it is given that U's issue is ranked 7th and there is one officer between U and the officer whose issue is ranked 2nd, and in statement 3 it is given that the officer whose issue is ranked 1 is not opposite to the officer whose issue is ranked 8 who represents issues related to Investments.

Final arrangement:

If the officer V is to the immediate right of the officer representing Trade Facilitation, then the officer $$4^{th}$$ to the right of V discusses investments.
The answer is option D.

In statement (1) is is given that P is sitting to the immediate left of S and the officer opposite to S discusses issues pertaining to Remedies and in statement (7) it is given that P's issue was ranked 4th and he was discussing issues related to Tariffs and sits opposite to the officer ranked 5th who represents issues related to Subsidies. Therefore,

In statement 5 it is given that the officer discussing issues related to Trade in Services is sitting opposite to T. T is sitting at a gap of one place from P and in statement 8 it is given that the officers representing issues related to Trade in Services and Trade facilitation are sitting adjacent to each other. The only possible arrangement considering statement 6 as well is as shown below.

In statement 2 it is given that U's issue is ranked 7th and there is one officer between U and the officer whose issue is ranked 2nd, and in statement 3 it is given that the officer whose issue is ranked 1 is not opposite to the officer whose issue is ranked 8 who represents issues related to Investments.

Final arrangement:

Issues that can be represented by W is Trade in Services or Subsidies.
The answer is option C.

In statement (1) is is given that P is sitting to the immediate left of S and the officer opposite to S discusses issues pertaining to Remedies and in statement (7) it is given that P's issue was ranked 4th and he was discussing issues related to Tariffs and sits opposite to the officer ranked 5th who represents issues related to Subsidies. Therefore,

In statement 5 it is given that the officer discussing issues related to Trade in Services is sitting opposite to T. T is sitting at a gap of one place from P and in statement 8 it is given that the officers representing issues related to Trade in Services and Trade facilitation are sitting adjacent to each other. The only possible arrangement considering statement 6 as well is as shown below.

In statement 2 it is given that U's issue is ranked 7th and there is one officer between U and the officer whose issue is ranked 2nd, and in statement 3 it is given that the officer whose issue is ranked 1 is not opposite to the officer whose issue is ranked 8 who represents issues related to Investments.

Final arrangement:

The officer to the $$4^{th}$$ right to the officer discussing the issues related to Remedies, is discussing Trade Facilitation.
The answer is option B.

It is given, y = 2x
z > y and z is even
y = 2x
2y + 3x + z + 2 = 30
7x + z = 28
Only x = 2 and z = 14 satisfies the given conditions.
Maximum common products both Dora and Sara can export = Products common to Machines and Intermediates only = x = 2
The answer is option A.

It is given, y = 2x
z > y and z is even
y = 2x
2y + 3x + z + 2 = 30
7x + z = 28
Only x = 2 and z = 14 satisfies the given conditions.
The total number of products which both Abeer and Dora export = Intermediate + Machine - Homemade = 14 + 2 + 4 = 20
The answer is option B.

Step 1 - Banana(1) is(2) the(3) favourite(4) fruit(5) of(6) Bina(7)
10 am - 1 2 3 4 5 6 7
11 am - 3 2 6 4 7 5 1
12 - 6 2 5 4 1 7 3
3 pm - 5 2 7 4 3 1 6
4 pm - 7 2 1 4 6 3 5
5 pm - 1 2 3 4 5 6 7 
6 pm - 1 2 3 4 5 6 7
7 pm - 3 2 6 4 7 5 1
8 pm - 6 2 5 4 1 7 3
9 pm - 5 2 7 4 3 1 6
It is given that fourth show code is 'All of Delhi welcome to the show', i.e. 5 2 7 4 3 1 6. First show code will be 'The of to welcome All show Delhi'. The answer is option C.

Step 1 - Banana(1) is(2) the(3) favourite(4) fruit(5) of(6) Bina(7)
10 am - 1 2 3 4 5 6 7
11 am - 3 2 6 4 7 5 1
12 - 6 2 5 4 1 7 3
3 pm - 5 2 7 4 3 1 6
4 pm - 7 2 1 4 6 3 5
5 pm - 1 2 3 4 5 6 7 
6 pm - 3 2 6 4 7 5 1
7 pm - 6 2 5 4 1 7 3
8 pm - 5 2 7 4 3 1 6
9 pm - 7 2 1 4 6 3 5
It is given that the entry code for the show at 7 pm is 'Do things to help others in difficulty', i.e. 6 2 5 4 1 7 3. We need to find entry code for 12 noon show, i.e. 6 2 5 4 1 7 3 which is the same as the code for the show at 7 pm.
The answer is option B.

The author explains cultural metamorphosis in different context.

He then attempts to introduce the different facets of cultural metamorphosis and explains them in different contexts. 

Hence, the correct answer is option D

"Society, it has been said, is what emerges from a network of interactions between people that follow certain agreed upon and perceptible patterns. These are determined by ideas of status, hierarchy and a sense of community governing the network. They are often, but not invariably, given a direction by those who control the essentials in how a society functions, as for instance, its economic resources, its technology and its value systems."

From the above lines, it is clear that option B is the correct answer.

Option A: The passage mentions inequalities in society, such as differences in wealth and social standing, but it doesn’t define society solely on the presence of "rich and poor."

Option C: While the passage discusses inequalities and how some individuals have more control over resources (such as economic power, technology, etc.), it does not define society solely in these terms.

Option D: This is just an example and not what defines society as per the passage.

"Every. society has its cultures, namely, the patterns of how the people of that society live. In varying degrees this would refer to broad categories that shape life,"

"There is a historical dimension to each of these as culture and history are deeply intertwined. There is also an implicit dialogue between the present and the past reflected in the way in which the readings of the past changed over historical periods."

Consider the above two lines. It can be inferred from these lines that option C is the correct answer.

In third paragraph, it is given 'the public intellectual has, by definition, to be liberal, that is, to insist that there be space to present varying perspectives and that wherever possible, reason and ethics should have primacy in whatever debates are taking place.' Option B is the appropriate answer.

The answer is option B.

The author thinks that public thinkers in the past were seen as more independent and likely to speak their minds. But today, public thinkers (like academics) might be more worried about getting in trouble with people in power, so they might not speak as freely.

The answer is option D.

orthodox - following or conforming to the traditions and beliefs of particular religion or philosophy (lack of other knowledge)
orthoprax - an intellectual perspective, the one who posses knowledge to social concerns as well. 
heterodox - the one who expands his sphere to external world
Heterodoxy matches with author's idea on public intellectual. The answer is option B.

The third paragraph it is mentioned that there is an over reliance on information leading to complacency in decision making. Option D captures the point mentioned in the passage. Option C is contradictory. Option A is partially correct, author also mentions that there need to be a shift in our thoughts and actions. Option B is incorrect as it says information is important. The answer is option D.

In second paragraph it is mentioned that how today's leaders have more information and spend time on analysing the information instead of reacting. Options B captures the point mentioned in the passage. The answer is option B.

In second and thirds paragraphs, author clearly mentions the shift required from information to interaction to take effective decisions. In third paragraph, author also mentions that the agility shift requires that we value our capacity to connect and build relationships over-or at least as much' as-our hard-won expertise. Therefore, the answer is option C.

In first paragraph, it is mentioned that we operate under the illusion that if we can gain more information, we will not only understand what is happening, we might just be able to control it. Among the given options, option C is the most appropriate one.
The answer is option C.

Option A captures the main point of the passage, i.e. STEM skills and social liberal skills both are required to develop products which are most relevant today. Option B and C do not consider social liberal skills. Option D is too extreme by saying can solve all the problems. The answer is option A.

Option C best captures the point mentioned in the passage. In the passage, nowhere it is discussed about the price of products. Therefore, option B is incorrect. 

Option A did not mention the point on how products should help to deal with variety of social problems. 

In the passage, nowhere it is mentioned that products should be similar to human beings. 

Hence, the answer is option C.

The author thinks that people who study things like history, literature, and social sciences (liberal arts) are really good at understanding people. This helps them make technology that actually fits what humans need and want. People in science and technology fields (STEM) are great at building the technology, but the liberal arts folks are key to making it feel more human.

Options A and C are clearly incorrect. Option B is incorrect because the author gives examples where liberal arts students contributed to technological innovations. The answer is option D.

In last paragraph it is mentioned that GDP estimates a snapshot of GDP(only economic perception) at a single point in time, but nothing more. A large GDP can indicate that a country is rich yet mask that its economy might be struggling and scarcely growing. This implies that GDP provides accurate and incomplete information.
The answer is option C.

As per the passage, Non GDP measures such HDI, SPI goes beyond the economic factors, i.e. social progress, education, well being, quality of life etc., Option C captures the point correctly. The answer is option C.

The passage highlights that GDP is a valuable economic indicator that measures economic performance, but it doesn't capture other important factors like happiness, well-being, and social progress. Non-GDP measures, such as the World Happiness Report, HDI, and Social Progress Index, provide a broader picture that can reveal gaps in public policy, focusing on social and environmental aspects beyond just economic performance. This is captured in Option C.

Option A: The passage does not claim that GDP correlate to overall success or that non-GDP measures do not contribute to understanding social progress.

Option B: The passage mentions non-GDP indices as being important and valuable, and while they may not be perfect, they aren't open to interpretation. They aim to assess different dimensions of social progress, which can also inform policy decisions.

Option D: The passage does not mention that most countries do not accept non-GDP measures.

The word we get on solving the puzzle is "loquacious"  which is the tendency to talk a lot. While there is no option which gives an exact synonym, Verbose (A) refers to a person who uses more words than necessary to express himself.

The word we get on solving the puzzle is "macabre" which is an adjective meaning disturbing or gruesome (C).

The word we get on solving the puzzle is "pernickety" which means to give too much importance to trivial details or in other words, fussy (D).

Cicerone is a person who gives information about a place or a monument to sightseers (like a tour guide).
Dragoman is a person who interprets languages. Hence the word we are looking for is Interpreter (B).

Sylvan is a word that describes something associated with woods. 
Similarly, terrestrial is a word that is used to describe something that is associated with earth.
Hence the answer is Earth (C).

Here we are looking for words such that the second word is usually seen as a result of the first and we should keep in mind that the sentence is about a business partnership (from the use of the word franchiser). So we can eliminate options A and B. 
Option D is a good choice, but it would have been better if the second word was of a more positive essence. 
Hence we go with option D, which fulfils all the criteria. 

The sentence implies that evaluating long essays is not easy for teachers. Hence, the right pair of words in the given context is handle and weighing. The answer is option D.

Starting with the second blank, the word we are looking for should have the essence of oppression or suffering and should be in the plain form. So, the first blank should contain a word that means the opposite of the second blank. Thrive and Suffer are the only two words from the option that correctly fill the first and second blank, respectively. 

1. Adonis is a Greek mythological character, and in English, the word means a handsome young man. (c)
2. Don Juan is a legendary Spaniard known as a great lover or seducer. (d)
3. Wastrel means someone good for nothing. (a)
4. A lout is an aggressive man or boy. (b)

1. En Masse means "in a group". It qualifies the action or verb. Hence it is an adverb. (c)
2. Fetter is an object used to restrain prisoners. It is a noun. (d)
3. Malinger is the act of pretending to be ill. It is a verb. (b)
4. Raspy is a word used to describe a sound that is hoarse or harsh. Hence it is an adjective. (a)

The job is much worse than I expected. If I "had" realised how awful it was going to be, I would not have accepted it.

The usage of "has" in (b) is incorrect as "luminaries" is plural.

Adapted from the Portuguese word "Auto-da-fe", it has the same meaning.

"Voracious" means to devour enormous quantities of food. It traces its origin to the Latin word "vorare" which means the same. 

"Echt", is adapted from the same word in German means typical or authentic.

The word aegis means protection or support and the word is derived from the Greek mythology where "aigis" is the shield of Zeus.

Options A and D have errors in parallelism. Option B mentions 'from...and to' which is not correct. Option C is correct, considering all the aspects. The answer is option C.

The idea conveyed by the whole sentence is that while the square root of a negative number has no real value, equations involving such numbers may have practical applications. Due to the usage of "not necessarily," the answer we are looking for should be phrased as "such equations have no practical applications" and the double negation will give the sentence a positive essence.

The only answer that conveys the required sense is B.

B is an opening statement in which it is suggested that that RBI has taken over several aspects of monetary policies from the government. A indicates that despite having certain powers, the final decision rests with the government. C elaborates A with an example. D poses a question for the reader to decide after reading all the above statements.

Hence the correct order is BACD. 

Sentence A gives the basic premise of what is being discussed in the passage i.e. that all demands are subject to change. Thus, sentence A is apt as the opening sentence of the paragraph. D further discusses the individual demands and C discusses aggregate demand. DC discuss the demands chronologically and hence ADC is the mandatory pair. B is driving the paragraph on a tangential nuanced idea apart from demand. Thus ADCB is the right choice.

Z's funds = 10000 x 100/5 = 2 lakhs

Y has funds which are 2 times the funds of Z => 4 lakhs

X has given loan to Y which is equal to 10% of funds of Y

y's funds + 10% of Y's funds = 4 lakhs

Y's funds = 4/1.1 lakhs

Y's donation = 5/100 (4/1.1lakhs) = 18181.81 

Let height of liquid level before the ball was dropped be h

The radius of the surface of the liquid level then is 4cm

We know that the volume of the bucket or frustum is V = $$\frac{1}{3}\pi h(R^2+r^2+Rr)$$

$$\frac{h}{3}\pi\ \left(4^2+3^2+4\cdot3\right)\ =200cc$$

=> h = $$\frac{600}{37\pi\ }$$

The liquid level raises by 0.3h as a result of the solid metal ball being dropped.

By similarity, the radius of the surface of the liquid level after metal ball is dropped is 4.3cm

Volume of he solid metal ball = $$\frac{1.3h}{3}\left(4^2+3^2+4.3\left(3\right)\right)\ -\ 200$$ = 83.82cc

The base on any one of the lines can be formed in $$5_{C_2}=10\ ways$$

To form a triangle, the base has to be joined to any of the 15 points on the other lines

Number of triangles that can be drawn when the base is on any of the lines = 10 *15 =150

and number of triangles that can be drawn totally = 150*4 = 600

S is the midpoint of QR. So, area of PSR = $$\frac{1}{2}\left(Area\ of\ PQR\right)\ =\ \frac{5.8}{2}=2.9$$

PT||XS

So area of XSP = area of XST ( same height and same base)

Adding area of XSR on both sides, we have area of PSR = Area of RTX

=>  area of PSR = Area of RTX = 2.9 sq.cm

Q(x,y) = x^2- xy + y^2.$$

Q(9,4) = $$9^2-4\cdot9+4^2=81+16-36=61$$

P(7,61) = $$7^2+7\cdot61+61^2=\ 49+427+3721=4197$$

PA = QB and A=B = $$90^{\circ\ }$$

=> PQBA is a rectangle.

Area of the shaded region = (Area of PQBA - Area of the segment PRQ)

$$PQ=AB=25\sqrt{\ 5}$$

$$PO=QO=\frac{PQ}{\sqrt{\ 2}}=25$$ = radius of the circle.

The perpendicular from O to PQ is $$\frac{25}{\sqrt{\ 2}}$$

Distance from the foot of the perpendicular to AB = $$30-\frac{25}{\sqrt{\ 2}}$$

Area of PQBA = $$\left(30-\frac{25}{\sqrt{\ 2}}\right)\left(25\sqrt{\ 2}\right)=750\sqrt{\ 2}-625$$

Area of segment PRQ = Area of sector OPRQ - Area of triangle OPQ = $$\frac{90}{360}\pi\ 25^2-\frac{1}{2}25^2$$

Area of shaded region = $$\left(750\sqrt{\ 2}-625\right)-\left(\frac{90}{360}\pi\ 25^2-\frac{1}{2}25^2\right)$$

= option C

$$\alpha\beta\ \ =\ 14$$

$$\alpha\ +\beta\ \ =\ 8$$

$$(1 + \alpha + \beta^2)(1 + \beta + \alpha^2)$$ = $$1+\beta\ +\alpha\ ^2+\alpha\ +\alpha\ \beta\ +\alpha\ ^3+\beta\ ^2+\beta\ ^3+\left(\alpha\ \beta\ \right)^2$$

 $$\alpha\ ^2+\beta\ ^2=\left(\alpha\ +\beta\ \right)^2-2\alpha\ \beta\ \ =\ 64-28\ =\ 36$$

$$\alpha\ ^3+\beta\ ^3=\left(\alpha+\beta\ \ \right)^3-3\alpha\ \beta\ \left(\alpha\ +\beta\ \right)=512-336=176$$

Hence $$1+\beta\ +\alpha\ ^2+\alpha\ +\alpha\ \beta\ +\alpha\ ^3+\beta\ ^2+\beta\ ^3+\left(\alpha\ \beta\ \right)^2$$ = 1 + 8 + 36+176+14 + 196 = 431

The equation becomes

==>$$\frac{1}{\log_x yz + log_x x} + \frac{1}{\log_y xz + log_y y} + \frac{1}{\log_z xy + log_z z}$$

$$\frac{1}{\log_x xyz} + \frac{1}{\log_y xyz} + \frac{1}{\log_z xyz}$$

$$log_{xyz} xyz$$

=1.

Part of the work  completed on Monday, Tuesday and Wednesday = 1/9 +1/12 + 1/15 = 47/180

Part of the work completed at the end of 9 days of work = 47(3)/180 = 47/60

remaining part of the work= 13/60 = 39/180

Part of the work completed by ram on 10th day = 1/9 = 20 /180

Part of the work completed by Rvi on 11th day = 1/12 = 15/180

remaining part of the work = 4/180

Ratan can do 12//180th of work on 12th day. Hence he needs 1/3rd of the 12th day.

Proportion of the completed work done by Ravi = 3(1/12) + 15/180 = 1/3

 Let the side of the square x be denoted by $$S_x$$

Let the radius of the circle y be denoted by $$r_y$$ and diameter by $$d_y$$

$$S_{s1}=4$$

$$r_{c1}=\frac{d_{c1}}{2}=\frac{4\sqrt{\ 2}}{2}=2\sqrt{\ 2}$$

$$S_{s2}=d_{c1}=4\sqrt{\ 2}$$

$$r_{c2}=4$$

..

.

.

A1 = $$\pi\ r_{c1}^2-S_{s1}^2\ =\ 8\pi\ -16$$

A2 = $$16\pi\ -32$$

A3 = $$32\pi\ -64$$

Sum = $$\frac{\left(8\pi\ -16\right)\left(2^n-1\right)}{2-1}\ =\ \left(8\pi\ -16\right)\left(2^n-1\right)$$

Ratio = $$\left(2^n-1\right)$$

Since the value of n is unknown, the answer can be C or D

Speed of joseph = 50/60 = $$\frac{5}{6}$$ m/s

Let the radius of circular playground be r

Speed = distance/ time

Time to diametrically cross a semi-circular playground t1= $$\frac{2r}{\frac{5}{6}}$$ = $$\frac{12r}{5}$$

Time to cross the playground along the semi-circular path t2 = $$\frac{\pi\ r}{\frac{5}{6}}=\frac{\left(6\pi\ r\right)}{5}$$

t1-t2 = 48

$$\frac{12r}{5}-\frac{\left(6\pi\ r\right)}{5}\ =\ 48$$

=> r = 35m

hence diameter = 70m

Garima had x notes of Rs 2000. She gave x/2 notes of Rs 2000. She is left with x-x/2 = x/2 notes

x/2  + 30 = 1.75x/2

=> x= 80

So, she remains 80/2 = 40 Rs 200 notes

So she must be having 50-40 = 10 Rs 200 notes.

H - volume of hole
R - volume of remaining solid
T - Total volume
It is given, $$H\ =\ \frac{1}{3}R$$
H + R = T
T = 4H
$$\frac{1}{3}\pi\ \left(25\right)\left(2x\right)+\pi\left(25\right)\left(3x\right)=4\times\pi\ r^2\left(\frac{10}{3}x\right)$$
$$r^2=\frac{275}{40}$$
$$r\ =\sqrt{\frac{\ 55}{8}}$$
The answer is option D.

Tap A alone can fill the tank in 12 hours
Tap B alone can fill the tank in 12*1.5 = 18 hours
Tap C alone can empty the tank in 36 hours
Let the total volume of the tank be 36 units
A fills 3 units, B fills 2 units and C empties 1 units in an hour.
Let the total time taken be 't'
t(3) + (t-2)2 - 6(1) = 36
5t = 46
t = 9.2 hrs = 9 hours 12 minutes
The answer is option C.

Let the point intersecting inside triangle ABC be 'E'.
It is given, $$\ \angle\ AED$$ = 60, $$\ \angle\ ABC$$ = 45, $$\ \angle\ EBC$$ = 30 and BE = 100
At point E, $$\ \angle\ BEF\ =60,\ \angle\ DEF=90\ and\ \angle\ AED\ =\ 60$$
$$\ \angle\ AEB\ =\ 360\ -\ 60\ -\ 60\ -\ 90\ =\ 150$$
In triangle AEB, $$\ \angle\ EAB\ =\ 180\ -\ 150\ -\ 15\ =\ 15$$
$$\ \angle\ EAB\ =\angle\ EBA$$
Therefore, EA = 100 (as BE = 100)
EF = DC = 50
In triangle AED, 
$$ED^2+AD^2=AE^2$$
ED = x, AD = $$\sqrt{\ 3}$$x
$$4x^2=\left(100\right)^2$$
2x = 100
x = 50
Height of summit = $$\sqrt{\ 3}x\ +\ 50$$ = $$50\left(\sqrt{\ 3}+1\right)$$
The answer is option A.

Total cost=Fuel cost+ Driver’s cost
Fuel cost=Total distance × Cost of Diesel per km
Fuel cost=1000×[1/400 {(1000/x)+x} ]×65
Fuel cost = 162500/x + 162.5x
Now, substituting the values from the given choices, we find that at x=36, the total cost is minimum.
Hence. Option B is correct.

It is given that 73% of those surveyed viewed at least one of the three Channels; this implies 27% viewed none of the channels
a + b + c + d + e + f + g = 73
It is given, g = 11
a + b + c + d + e + f = 62 ......... (1)
a + b + c + 2(d+e+f) + 3g = 38 + 39 + 23
a + b + c + 2(d+e+f) + 3g = 100
a + b + c + 2(d + e + f) = 67 .......... (2)
Subtracting (1) from (2), we get
d + e + f = 67 - 62 = 5
The percentage of those surveyed, viewed more than one of the three TV channels = d + e + f + g = 5 + 11 = 16
The answer is option A.

Probability of playing on grass = 0.6
Probability of playing on Artificial turf = 0.4
Probability of injury on artificial turf = $$\frac{3}{2}$$(probability of injury on grass)
0.42 = $$\frac{3}{2}$$(probability of injury on grass)
Probability of injury on grass = 0.28
Applying Baye's theorem,
Probability of injury on grass = $$\ \frac{\ 0.6\times\ 0.28}{0.6\times\ 0.28+0.4\times\ 0.42}\approx\ 0.5$$
The answer is option C.

$$1+x^2+\sqrt{\ 1+x^2+x^4}$$

=$$\frac{1}{2}\left(2+2x^2+2\sqrt{\ 1+x^2+x^4}\right)$$

=$$\frac{1}{2}\left(1+x+x^2+1-x+x^2+2\sqrt{\left(1+x+x^2\right)\left(1-x+x^2\right)}\right)$$

=$$\frac{1}{2}\left(\sqrt{\ 1+x+x^2}+\sqrt{\ 1-x+x^2}\right)^2$$

$$\sqrt{\ 1+x^2+\sqrt{\ 1+x^2+x^4}}=\sqrt{\frac{1}{2}\left(\sqrt{\ 1+x+x^2}+\sqrt{\ 1-x+x^2}\right)^2\ }$$

$$\sqrt{\ 1+x^2+\sqrt{\ 1+x^2+x^4}}=\frac{1}{\sqrt{\ 2}}\left(\sqrt{1+x+x^2}+\sqrt{\ 1-x+x^2}\ \right)$$

The answer is option A.

$$\log_ba\ =\ \frac{1}{\log_ab}$$

$$\log_2 x.\log_{\frac{x}{64}}2$$ = $$\frac{\log_2x}{\log_2\left(\frac{x}{64}\right)}=\frac{\log_2x}{\log_2x-6}$$

Similarly,

$$\log_{\frac{x}{16}}2$$=$$\frac{1}{\log_2x-4}$$

Let $$\log_2x=t$$ => $$\frac{t}{t-6}=\frac{1}{t-4}$$ => $$t^2-5t+6=0$$ => $$\left(t-2\right)\left(t-3\right)=0$$ => t=2,3

.'. $$\log_2x=2\ or\ 3\ =>\ x=4\ or\ 8.$$

Hence, B is correct.