[Download PDF] IBPS Clerk 2018 Paper with Solutions

Instructions

What will come in place of the question mark (?) in the given question?

Question 31

$$( 8 * 16 \div 256 * 512 ) \times \frac{1}{2^?} = 1$$

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Solution

Question 32

$$\frac{1}{5}of\frac{11}{13}of\frac{39}{55} of 1200=562-?$$

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Solution

Question 33

$$59-2\sqrt{5}*3\sqrt{5}=72-?$$

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Solution

Question 34

$$\frac{\sqrt{(6400)}-\sqrt{(625)}}{11}=?$$

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Solution

Question 35

$$\frac{1472}{?}+\frac{2925}{9}=965$$

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Solution

Instructions

In these questions, relationships between different elements is shown in the statements. The statements is followed by two conclusions. Study the conclusions based on the given statement and select the appropriate answer.

Question 36

Statement: K > I $$ \geq $$ T $$ \geq $$ E; O < R < K
Conclusions: I. R < E 2. O < T

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Solution

Question 37

Statement C < L < O = U = D $$ \geq $$ S > Y
Conclusions I. O > Y II. C<D

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Solution

Question 38

Statement K $$ \geq $$ L > M $$ \geq $$ N
Conclusions I. N $$ \leq $$ K II. N<K

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Solution

Question 39

Statement: Z $$ \geq $$ Y = W $$ \geq $$ X
Conclusions I. W<Z II. W=Z

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Solution

Question 40

Statement: B > A > S < I > C > L >Y
Conclusions I. B>L II. A>Y

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Solution

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IBPS Clerk 2018

IBPS Clerk 2018

$$( 8 * 16 \div 256 * 512 ) \times \frac{1}{2^?} = 1$$

$$\frac{1}{5}of\frac{11}{13}of\frac{39}{55} of 1200=562-?$$

$$59-2\sqrt{5}*3\sqrt{5}=72-?$$

$$\frac{\sqrt{(6400)}-\sqrt{(625)}}{11}=?$$

$$\frac{1472}{?}+\frac{2925}{9}=965$$

Statement: K > I $$ \geq $$ T $$ \geq $$ E; O < R < K Conclusions: I. R < E 2. O < T

Statement C < L < O = U = D $$ \geq $$ S > Y Conclusions I. O > Y II. C<D

Statement K $$ \geq $$ L > M $$ \geq $$ N Conclusions I. N $$ \leq $$ K II. N<K

Statement: Z $$ \geq $$ Y = W $$ \geq $$ X Conclusions I. W<Z II. W=Z

Statement: B > A > S < I > C > L >Y Conclusions I. B>L II. A>Y

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Statement: K > I $$ \geq $$ T $$ \geq $$ E; O < R < K
Conclusions: I. R < E 2. O < T

Statement C < L < O = U = D $$ \geq $$ S > Y
Conclusions I. O > Y II. C<D

Statement K $$ \geq $$ L > M $$ \geq $$ N
Conclusions I. N $$ \leq $$ K II. N<K

Statement: Z $$ \geq $$ Y = W $$ \geq $$ X
Conclusions I. W<Z II. W=Z

Statement: B > A > S < I > C > L >Y
Conclusions I. B>L II. A>Y