CMAT Alphabet and Mixed Series Questions

In the following group of letters, CE has one latter gap between them ( C_E). IK has one letter gap (I_K), SV has (S_ _ V) two letter gap, FH has one letter gap between them (F_H), and UW has one letter gap (U_W).

Hence, all the groups of letters have one letter gap between the first letter and the second letter, except SV. Hence, SV is the odd one out.

The correct option is A.

1st letters of each term are : C, E, G, ?, K 

We can observe that these are alternate alphabets of english alphabets 

Hence, we can say that the first alphabet of the missing term will be I 

2nd letter of each term are : A, E, I, ?, U 

We can observe that there is gap of exactly 3 alphabets between any 2 consecutive terms. 

Hence we can say that the second alphabet of the missing term will be O

3rd letter of each term are :T, R, P, ?, L 

We can observe that these are alternate alphabets in descending order. 

Hence we can say that the third alphabet of the missing term will be N

Firstly, (564/4) = 141+11 => 152.

(152/4) = 38+10 => 48

(48/4) = 12+9 => 21, and (21/4)+8 = 13.25

Hence the next term is 13.25. The correct option is D

In the top left quarter of circle we can observe that 

$$\left(3^2+4^2\right)\times3\ =\ 75$$

In the top right corner 

$$\left(7^2+9^2\right)\times3\ =\ 390$$

In the bottom left corner 

$$\left(11^2+8^2\right)\times3\ =\ 555$$

In the bottom right corner 

$$\left(13^2+5^2\right)\times3\ =\ 582$$

Considering the first letters of each term.

There are 2 alphabets in between D and G (E and F). 

There are 3 alphabets between G and K (H, I and J).

There are 4 alphabets between K and P (L, M, N, and O)

Hence, there will be 5 alphabets between P and the required letter. Thus, the required letter will be V (Q, R, S, T and U)

Considering the second letter of each term.

There are three alphabets between each of the second terms, I and M (J, K, L), M and Q (N, O, P), and Q and U (R, S, T).

Hence, there will be three terms between the required term and U, i.e., V, W, X. Thus, the required second term is Y.

Hence, the answer is option A.

From the 2nd term onwards,

1st letter of every term is 2nd letter of the previous term

2nd letter of every term is 3rd letter of the previous term

3rd letter of every term is 1st letter of the previous term

2nd term is AQF so as per the above logic third term will be QFA.

All the terms are of the form $$x^2-1$$

$$5^2-1=24$$, $$7^2-1=48$$, $$8^2-1=63$$ therefore $$6^2-1=35$$ is the correct answer.

Take 1st letter of all terms we get a series 
F,I,L,O,R we get next as U
Taking 2nd letter of all terms we again get a series with a pattern :
A,C,E,G,I so next will be K
so we get answer as UKR

210-195 =15 ; 195-175 =20 ; 175-150 =25 ; 150-120 =30 
so we get next number as 120-35 =85

Now 5671-2835 =2836
8505-5671 =2834
Now 11344-8505=2839
Now the difference should have been 2832 so we can say 11344 is the wrong term or it do not belong the group

The number in missing term should be 4 
The alphabets in 1st term are BCD then DEF so next will be FGH
Now the pattern is B2CD ,DE3F,FGH4

The digits at odd places are getting double than the previous odd digit 
so we get 7,14,28 , 56
so 56 is the answer.

Considering the first letter of given terms 
it forms pattern
C , I ,O,_ ,A
I and C have 5 alphabets between them , I and O also have 5 alphabets between them so we get first term as U .
Now considering 2nd letter of given terms :
D,J,P _,B
Here again D and J have 5 alphabets between them
J and P have 5 alphabets between them
So next letter will be V
so we get UV
We can conclude the answer will be UVXY

The pattern followed after filling all the blanks.

(A) : a b ab a b a b a b a b

(B) : b a a b a a b b a b a b

(D) : b b a b a a b b a a a b

If we look carefully, we can find only first option making a pattern, ab/ab/ab/ab/ab/ab

=> Ans - (A)

The pattern followed is that odd multiples of 3 (starting from 9 are added).

3 + 9 = 12

12 + 15 = 27

27 + 21 = 48

48 + 27 = 75

75 + 33 = 108

108 + 39 = 147

=> Ans - (B)

Expression = FJUL : BOQQ :: LHRX :

The pattern followed is :

Similarly, LHRX : HMNC

=> Ans - (B)

RUSTICATE is written as QTTUIDBSD

The pattern followed is :

Similarly, STATISTIC : 

=> Ans - (A)

The correct order as silkworm produces silk and then after yarn, in the end saree is made : 

Silkworm -> Silk -> Yarn -> cloth -> Saree

=> Ans - (B)

In the first pair of pictures, a triangle is formed by joining two hypotenuse triangles, and the second picture shows left side triangle with a shade, similarly, for the two semi circles, we need one on the left side, i.e. curve on left with grey shade, as shown in first figure.

=> Ans - (A)

As per the pattern 

will be the next figure .

In each row, the pattern followed is there are consecutive even or odd numbers as

(9,11,13), (13,15,17), (10,12,14)

Similarly, the missing series will be : 14,16,18 and 11,13,15

Thus, missing values = 18, 15

=> Ans - (D)

The pattern followed is that '4' and '2' are alternatively added.

24 + 4 = 28

28 + 2 = 30

30 + 4 = 34

34 + 2 = 36

=> Ans - (D)

Alternatively, the arrows are facing downwards, and towards the right. Also, it gets decrease by 1 in each alternate figure. Thus, in the fifth figure, there will be 3 arrows facing downwards as shown in 3rd figure.

=> Ans - (A)

The numbers are of the form $$2^n$$ where $$n$$ is in decreasing order starting from 1.

$$2^{1}=2$$

$$2^{0}=1$$

$$2^{-1}=\frac{1}{2}$$

$$2^{-2}=\frac{1}{4}$$

$$2^{-3}=\frac{1}{8}$$

=> Ans - (B)

In the problem figure, the second image is mirror image of first when horizontal mirror is placed, similarly the first option is the correct mirror image of the question figure.

In the second figure, number of lines are not equal, and the fourth image is the mirror replica when vertical mirror is placed.

=> Ans - (A)

Number of 7 in the given series that are followed by an even number but are not preceded by a prime number

= (not a prime number) (7) (even number)

2 3 7 4 3 2 1 5 7 3 2 7 1 0 9 8 7 5 4 7 2 3

Thus, there is only one such 7.

=> Ans - (A)

The middle number is the sum of numbers assigned to their adjacent alphabets as, A=1, B=2, C=3,.......,Z=26

EJO + TYE $$\equiv5+10+15+20+25+5=80$$

DHL + PTX $$\equiv4+8+12+16+20+24=84$$

Similarly, CFI + LOR $$\equiv3+6+9+12+15+18=63$$

=> Ans - (A)

0 = 1$$^2$$-1

6 = 2$$^2$$+2

6 = 3$$^2$$-3

20 = 4$$^2$$+4

20 = 5$$^2$$- 5

42 = 6$$^2$$ + 6

Option A is correct.