Question 21

Identify odd group of letters:
CE, IK, SV, FH, UW

Solution

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In the following group of letters, CE has one latter gap between them ( C_E). IK has one letter gap (I_K), SV has (S_ _ V) two letter gap, FH has one letter gap between them (F_H), and UW has one letter gap (U_W).

Hence, all the groups of letters have one letter gap between the first letter and the second letter, except SV. Hence, SV is the odd one out.

The correct option is A.

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