AP ICET 2018 Question Paper Shift-1 (2nd May)

Let the total work = W

Number of days required for 9 women to finish the work = 19 days

$$\Rightarrow$$  Work done by 9 women in 1 day = $$\frac{W}{19}$$

$$\Rightarrow$$  Work done by 1 woman in 1 day = $$\frac{W}{19\times9}$$

5 men or 9 women can finish the work in 19 days

$$\Rightarrow$$ 5 men = 9 women

$$\Rightarrow$$ 1 men = $$\frac{9}{5}$$ women

3 men and 6 women = 3($$\frac{9}{5}$$women) + 6 women = $$\frac{27}{5}$$ women + 6 women = $$\frac{57}{5}$$ women

Work done by $$\frac{57}{5}$$ women in 1 day = $$\frac{57}{5}\times\frac{W}{19\times9}$$ = $$\frac{W}{15}$$

Number of days required for $$\frac{57}{5}$$ women to complete the work = 15 days

$$\therefore\ $$Number of days required for 3 men and 6 women = 15 days

Area of sector = $$\frac{\theta}{360}\cdot\pi\ r^2=\frac{77}{3}$$

=> $$\frac{\theta}{360}\cdot\frac{22}{7}\cdot7^2=\frac{7}{3}$$

=> angle = 60

Let length = 3b and breadth =b

Permiter = 2(b+3b) = 96

=> 4b= 48 => b=12

Hence l = 36 and b = 12

Area = 36*12 = 432

Let thickness = a meters

According to the problem,

a x 10000 m$$^2$$ = 1 m$$^3$$

$$\Rightarrow$$ a x 10000 = 1 m

$$\Rightarrow$$ a x 10000 = 100 cm

$$\Rightarrow$$ a = $$\frac{1}{100}$$ cm

$$\Rightarrow$$ a = 0.01 cm

Hence, the correct answer is Option D

Given,  h = 2b

Area of parallelogram = base x height

$$\Rightarrow$$  b x h = 128

$$\Rightarrow$$  b x 2b = 128

$$\Rightarrow$$  b$$^2$$ = 64

$$\Rightarrow$$  b = 8 cm

$$\therefore\ $$Base of parallelogram = 8 cm

Let length = l

Breadth = b

Given, lb=120 and l+b = 23

Squarring on both sides, $$l^2+b^2+2lb\ =\ 529$$

$$l^2+b^2=\ 529\ -\ 2\left(120\right)$$

=> $$l^2+b^2=\ 289$$

Lenth of diagonal = $$\sqrt{l^2+b^2\ }=\ \sqrt{\ 289}\ =17$$

$$3214_{(7)}$$ = $$4\left(7^0\right)+1\left(7\right)+2\left(7^2\right)+3\left(7^3\right)=\ 1138$$

$$\therefore\ $$In decimal system, $$3214_{(7)}$$ = $$1138_{(10)}$$

Hence, the correct answer is Option A