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If 5 men or 9 women can finish a piece of work in 19 days, then the number of days for 3 men and 6 women to finish the same work is
Let the total work = W
Number of days required for 9 women to finish the work = 19 days
$$\Rightarrow$$Β Work done by 9 women in 1 day = $$\frac{W}{19}$$
$$\Rightarrow$$Β Work done by 1 woman in 1 day =Β $$\frac{W}{19\times9}$$
5 men or 9 women can finish the work in 19 days
$$\Rightarrow$$ 5 men = 9 women
$$\Rightarrow$$ 1 men =Β $$\frac{9}{5}$$ women
3 men and 6 women = 3($$\frac{9}{5}$$women) + 6 women =Β $$\frac{27}{5}$$ women + 6 women =Β $$\frac{57}{5}$$ women
Work done by $$\frac{57}{5}$$ women in 1 day = $$\frac{57}{5}\times\frac{W}{19\times9}$$ = $$\frac{W}{15}$$
Number of days required for $$\frac{57}{5}$$ women to complete the work = 15 days
$$\therefore\ $$Number of days required for 3 men and 6 women = 15 days
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