Question 102
In a circle of radius 7 cms, a sector is of $$\frac{77}{3}$$ sq.cms area. Then the sectorial angle is (Taking $$\pi = \frac{22}{7}$$)
Solution
Area of sector = $$\frac{\theta}{360}\cdot\pi\ r^2=\frac{77}{3}$$
=> $$\frac{\theta}{360}\cdot\frac{22}{7}\cdot7^2=\frac{7}{3}$$
=> angle = 60
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