AP ICET 2nd May 2018 Shift-1

Question 109

$$3214_{(7)}$$ in decimal system is

Solution

$$3214_{(7)}$$ = $$4\left(7^0\right)+1\left(7\right)+2\left(7^2\right)+3\left(7^3\right)=\ 1138$$

$$\therefore\ $$In decimal system, $$3214_{(7)}$$ = $$1138_{(10)}$$

Hence, the correct answer is Option A


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