RPF 10 Jan 2019 Slot 1 Question 98

Question 98

Find the number of trailing Zeros in 243!

Solution

Number of trailing zeroes = $$\frac{243}{5}+\frac{243}{25}+\frac{243}{125}$$

= $$48+9+1=58$$     [Number will be round off to the lowest value]

=> Ans - (C)



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