If the length of the side of an equilateral triangle is 6 cm, what is its area?
Side of an equilateral triangle, $$a=6$$ cm
Area = $$\frac{\sqrt{3}}{4}(a)^2$$
= $$\frac{\sqrt{3}}{4} \times (6)^2 = \frac{36\sqrt{3}}{4}$$
= $$9\sqrt{3}$$ $$cm^2$$
=> Ans - (D)
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