In a triangle ABC, AD is angle bisector of ∠A and AB : AC = 3 : 4. If the area of triangle ABC is 350 cm2, then what is the area (in cm2: of triangle ABD?
In $$\triangle$$ ABC, since AD is the angle bisector and AB : AC = 3 : 4
=> $$\frac{ar(\triangle ABD)}{ar(\triangle ADC)}=\frac{3}{4}$$
Also, $$ar(\triangle ABC)=350$$ $$cm^2$$
$$\therefore$$ $$ar(\triangle ABD)=\frac{3}{(3+4)}\times350$$
= $$3\times50=150$$ $$cm^2$$
=> Ans - (A)
Create a FREE account and get:
