Question 92
ABC is an equilateral triangle and P is the orthocenter of the triangle, then what is the value (in degrees) of ∠BPC?
Solution
Given : ABC is an equilateral triangle and P is the orthocenter
To find : $$\angle BPC = ?$$
Solution : ABC is an equilateral triangle and thus $$\angle A=60^\circ$$
Also, $$\angle BPC = 90^\circ+\frac{\angle A}{2}$$
= $$90+\frac{60}{2}$$
= $$90+30=120^\circ$$
=> Ans - (B)
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