Question 92

ABC is an equilateral triangle and P is the orthocenter of the triangle, then what is the value (in degrees) of ∠BPC?

Solution

Given : ABC is an equilateral triangle and P is the orthocenter

To find : $$\angle BPC = ?$$

Solution : ABC is an equilateral triangle and thus $$\angle A=60^\circ$$

Also, $$\angle BPC = 90^\circ+\frac{\angle A}{2}$$

= $$90+\frac{60}{2}$$

= $$90+30=120^\circ$$

=> Ans - (B)

Share on Whatsapp Share on Whatsapp

Create a FREE account and get: