Question 92

How many diagonals are there in octagon?

Solution

Number of diagonals in a polygon with $$n$$ sides = $$\frac{n(n-3)}{2}$$

An octagon has 8 sides

=> Number of diagonals = $$\frac{8(8-3)}{2}$$

= $$4\times5=20$$

=> Ans - (C)

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